We need to specify that we want to replace a string that contains a single backslash. We cannot write that as "\", because the backslash is escaping the intended closing double-quote. We also cannot use a raw string literal for this: r"\" does not work.
Instead, we simply escape the backslash using another backslash:
result = string.replace("\\","")
We need to specify that we want to replace a string that contains a single backslash. We cannot write that as "\", because the backslash is escaping the intended closing double-quote. We also cannot use a raw string literal for this: r"\" does not work.
Instead, we simply escape the backslash using another backslash:
result = string.replace("\\","")
The error is because you did not add a escape character to your '\', you should give \\ for backslash (\)
In [147]: foo = "a\c\d" # example string with backslashes
In [148]: foo
Out[148]: 'a\\c\\d'
In [149]: foo.replace('\\', " ")
Out[149]: 'a c d'
In [150]: foo.replace('\\', "")
Out[150]: 'acd'
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Easiest way to replace HTML entities and non-unicode stuff with the actual characters?
Doesn't seem realistic to map the characters manually -- in addition to the decimal & #123; syntax there's also a hex & #x123; syntax, and a named &name; syntax. You'd be there forever.
At the very least, you can decode the HTML entities first, and then after that step, replace the smart apostrophes with normal ones and whatever other replacements you plan to do.
However, a smart apostrophe is not invalid UTF-8. So I'm not sure why there is an error, and I don't know what charmap_encode is doing, I can't find documentation on it. It does have an errors property so you can supply a fallback character, but I don't see why you need it, since all Unicode characters can be represented in UTF-8.
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I have the following code.
The aim is to remove all special characters from the column of a DataFrame, although it does not matter if all special characters are removed from the DataFrame.
The code i have used is:
words = combined_body_title.title_body.str.split().explode().str.replace("[?.',)(/:!]","", regex=True)
This works until i put in quotation markets or brackets.
I have read the documentation, from that i think i am using it wrong. I should not be trying to change more than one character within the str.replace, but for some reason it still works just not for brackets and quotation marks.
If you could suggest an alternative solution or help me fix this one i would really appreciate it!