No. Regular expressions in Python are handled by the re module.
article = re.sub(r'(?is)</html>.+', '</html>', article)
In general:
str_output = re.sub(regex_search_term, regex_replacement, str_input)
No. Regular expressions in Python are handled by the re module.
article = re.sub(r'(?is)</html>.+', '</html>', article)
In general:
str_output = re.sub(regex_search_term, regex_replacement, str_input)
In order to replace text using regular expression use the re.sub function:
sub(pattern, repl, string[, count, flags])
It will replace non-everlaping instances of pattern by the text passed as string. If you need to analyze the match to extract information about specific group captures, for instance, you can pass a function to the string argument. more info here.
Examples
>>> import re
>>> re.sub(r'a', 'b', 'banana')
'bbnbnb'
>>> re.sub(r'/\d+', '/{id}', '/andre/23/abobora/43435')
'/andre/{id}/abobora/{id}'
How to test Python regex replace on regex101.com?
Why have to add regex = True to get .replace to work (pandas)
Hi,
The title may not be perfect but I could not think of a better one.
How am I able to do a regex search within a string and replace all occurrences with a modified version of the matching part?
Background:
The task I'm going to do is that I'm looking for regex for ISO datestamps and shift them according to a user-defined delta in days. Therefore, I'm looking for r'(?P<year>\d{4,4})-(?P<month>[01]\d)-(?P<day>[0123]\d)'. When I've got matches, I want to retrieve each match, add or subtract a delta in days to it and replace its original date-stamp accordingly.
I got the impression that re.subn() is not able to do something like this for me:
re.subn(r'(?P<year>\d{4,4})-(?P<month>[01]\d)-(?P<day>[0123]\d)', calculate_shifted_ISO_string_from_ymd(\1, \2, \3), line_to_parse)
Is my only option to separate the identification of matches, manually split the string for each occurrence, generate a datetime from the extracted string, add a delta-datetime in days and re-concatenate the result for all occurrences?
SOLUTION:
I chose the provided tip to use a function as described in the comments below.
The resulting tool which shifts ISO date-stamps within text-files is hosted on https://github.com/novoid/isodateshifter
Hello Very new to pandas. Trying to replace ampersand in my excel file
Why did I have to add regex=True to get this to work. It wouldn’t update otherwise.
df = df.replace(‘%26’ , ‘&’ , regex = True)