rounding - Round to 5 (or other number) in Python - Stack Overflow
How do you round a string in Python? - Stack Overflow
python - How do you round UP a number? - Stack Overflow
python - How to properly round-up half float numbers? - Stack Overflow
Greetings,
Code: x = round(7.85, 2) print(x)
Result: 7.8
Why is that? Rounding down starts at 0 and ends at 4, and rounding up begins at 5 and ends at 9. The result should be 7.9.
Does Python have its own math rules? If so, why? Math is math...
Please and thank you ☺
I don't know of a standard function in Python, but this works for me:
Python 3
def myround(x, base=5):
return base * round(x/base)
It is easy to see why the above works. You want to make sure that your number divided by 5 is an integer, correctly rounded. So, we first do exactly that (round(x/5)), and then since we divided by 5, we multiply by 5 as well.
I made the function more generic by giving it a base parameter, defaulting to 5.
Python 2
In Python 2, float(x) would be needed to ensure that / does floating-point division, and a final conversion to int is needed because round() returns a floating-point value in Python 2.
def myround(x, base=5):
return int(base * round(float(x)/base))
For rounding to non-integer values, such as 0.05:
def myround(x, prec=2, base=.05):
return round(base * round(float(x)/base),prec)
I found this useful since I could just do a search and replace in my code to change "round(" to "myround(", without having to change the parameter values.
You can use format strings:
print("The income tax is ${:.2f}".format(incomeTax))
If you are using Python 3.6+, you can also use f-strings:
print(f"The income tax is ${incomeTax:.2f}")
You can round just before making it a string:
print("The income tax is $" + str(round(incomeTax,2)))
Output:
Enter the gross income: 12345.67
Enter the number of dependents: 1
The income tax is $-130.87
The math.ceil (ceiling) function returns the smallest integer higher or equal to x.
For Python 3:
import math
print(math.ceil(4.2))
For Python 2:
import math
print(int(math.ceil(4.2)))
I know this answer is for a question from a while back, but if you don't want to import math and you just want to round up, this works for me.
>>> int(21 / 5)
4
>>> int(21 / 5) + (21 % 5 > 0)
5
The first part becomes 4 and the second part evaluates to "True" if there is a remainder, which in addition True = 1; False = 0. So if there is no remainder, then it stays the same integer, but if there is a remainder it adds 1.
The Numeric Types section documents this behaviour explicitly:
round(x[, n])
x rounded to n digits, rounding half to even. If n is omitted, it defaults to 0.
Note the rounding half to even. This is also called bankers rounding; instead of always rounding up or down (compounding rounding errors), by rounding to the nearest even number you average out rounding errors.
If you need more control over the rounding behaviour, use the decimal module, which lets you specify exactly what rounding strategy should be used.
For example, to round up from half:
>>> from decimal import localcontext, Decimal, ROUND_HALF_UP
>>> with localcontext() as ctx:
... ctx.rounding = ROUND_HALF_UP
... for i in range(1, 15, 2):
... n = Decimal(i) / 2
... print(n, '=>', n.to_integral_value())
...
0.5 => 1
1.5 => 2
2.5 => 3
3.5 => 4
4.5 => 5
5.5 => 6
6.5 => 7
For example:
from decimal import Decimal, ROUND_HALF_UP
Decimal(1.5).quantize(0, ROUND_HALF_UP)
# This also works for rounding to the integer part:
Decimal(1.5).to_integral_value(rounding=ROUND_HALF_UP)
You can use the round function, which takes as its first argument the number and the second argument is the precision after the decimal point.
In your case, it would be:
answer = str(round(answer, 2))
Using str.format()'s syntax to display answer with two decimal places (without altering the underlying value of answer):
def printC(answer):
print("\nYour Celsius value is {:0.2f}ºC.\n".format(answer))
Where:
:introduces the format spec0enables sign-aware zero-padding for numeric types.2sets the precision to2fdisplays the number as a fixed-point number