If x is a float number that you want to round up to an integer, and you want an integer type result, you could use

rounded_up_x = int(-(-x // 1))

This works because integer division by one rounds down, but using the negative sign before and after doing the division rounds the opposite direction. The int here converts the float result to an integer. Remove that int if you want a floating point value that equals an integer, which is what some programming languages do.

Hat-tip to @D.LaRocque for pointing out that Python's ceil() function returns an integer type.

int(x)

Conversion to integer will truncate (towards 0.0), like math.trunc.
For non-negative numbers, this is downward.

If your number can be negative, this will round the magnitude downward, unlike math.floor which rounds towards -Infinity, making a lower value. (Less positive or more negative).

Python integers are arbitrary precision, so even very large floats can be represented as integers. (Unlike in other languages where this idiom could fail for floats larger than the largest value for an integer type.)

The int function truncates a decimal number allowing you to round down to the next integer.

def round_down(x):
    return int(x)-1 if x < 0 else int(x)

round_down(3.5)   # 3
round_down(-4.6)  # -5