Replace find_element_by_xpath_selector with find_element_by_xpath (There is no find_element_by_xpath_selector method):

driver = webdriver.Firefox()
...
driver = driver.find_element_by_xpath(u"//td[contains(text(), 'hello')]")

COMPLETE EXAMPLE

from selenium import webdriver

driver = webdriver.Firefox()
driver.get('http://python.org')
link = driver.find_element_by_xpath(u'//a[contains(text(), "Download")]')
link.click()

No, css_selector for Selenium still doesn't supports :contains("text") method.

You can find a couple of detailed discussions in:

• selenium.common.exceptions.InvalidSelectorException with "span:contains('string')"
• Finding link using text in CSS Selector is not working

As you said it's supported in xpath:

This would be a solution with an xpath using contains and text()

driver.find_element_by_xpath('//div[@class="button-face-caption" and contains(text(),"Text I want to find")]')

The xpath being:

//div[@class="button-face-caption" and contains(text(),"Text I want to find")]

For css, look here: https://sqa.stackexchange.com/q/362/34209 which should allow us to use:

div:contains('Text I want to find')

Which would lead us to

driver.find_element_by_css("div:contains('Text I want to find')")

However this comes with a BIG caveat:

:contains() is not part of the current CSS3 specification so it will not work on all browsers, only ones that implemented it before it was pulled. (see w3.org/TR/css3-selectors)

css=a[text='Log Out'] or a[innertext='Log Out']

Can you please try this one out?

Or if that doesn't work and you still don't want to use xpath because it's slow, you can always try: link=Log Out. That's still better then xpath.

EDIT:

So i found a possible solution for you mate. If you are trying to find an exact String you could always use Regular expression like this:

css=div:contains("^ab$") 

Just replace div with a and there you go. This will find ONLY AB in whatever text div it looks for. OFC if you have more then one links with text AB (which is a bad thing :P ) then it will find them all..

Try this and see if it helps. :)

To print the value of the value attribute i.e. $10.50 you can use either of the following locator strategies:

• Using css_selector:

  print(driver.find_element_by_css_selector("input.form-control.OSFillParent[id$='Input_RemainAmtYr1']").get_attribute("value"))
  

• Using xpath:

  print(driver.find_element_by_xpath("//input[@class='form-control OSFillParent' and contains(@id, 'Input_RemainAmtYr1')]").get_attribute("value"))
  

Ideally you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following locator strategies:

• Using CSS_SELECTOR:

  print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "input.form-control.OSFillParent[id$='Input_RemainAmtYr1']"))).get_attribute("value"))
  

• Using XPATH:

  print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//input[@class='form-control OSFillParent' and contains(@id, 'Input_RemainAmtYr1')]"))).get_attribute("value"))
  

• Note : You have to add the following imports :

  from selenium.webdriver.support.ui import WebDriverWait
  from selenium.webdriver.common.by import By
  from selenium.webdriver.support import expected_conditions as EC
  

You can find a relevant discussion in Python Selenium - get href value