The answer is No, You can't use driver.find_element_by_class_name () or driver.find_elements_by_class_name () with multiple class names. It accepts only single class name.

However, you can use find_elements_by_xpath or find_element_by_css_selector method to achieve finding element with multiple class names.

for example below code will find element on google website using two different class names.

url= "http://google.com"
driver = webdriver.Chrome()
driver.get(url)
driver.find_elements_by_xpath("//*[@class='sfibbbc' or @class='jsb']")
# Following line will result in error 
driver.find_elements_by_class_name("sfibbbc jsb")

To select the div with the class you can use css (preferred for readability)

BY.css

Example

driver.find_element(By.CSS, 'div.dept-time')

or xpath

BY.xpath

Example

driver.find_element(By.XPATH, '//div[@class=dept-time]

or if there are multiple classes for that element, use

contains

Example

//div[contains(@class, 'dept-time')]

If more than 1 div element with that class exist and you want the first one you can also use:

[1]

Example (XPATH)

//div[@class='dept-time'])[1]

Example (CSS)

div.dept-time:first

Actually the two are quite different selectors.

Here is your cssSelector:

div#someId.aClass.andAnother input[type=text]

But what you really wanted to write was:

div#someId .aClass.andAnother input[type=text]

notice the space between ID and class. you need that.

I don't think barak manos's answer has fully explained it.

Imagine we have few elements as the followings:

1. <div class="value test"></div>
2. <div class="value test "></div>
3. <div class="first value test last"></div>
4. <div class="test value"></div>

How XPath matches

• Match only 1 (exact match), barak's answer

  driver.findElement(By.xpath("//div[@class='value test']"));
  

• Match 1, 2 and 3 (match class contains value test, class order matters)

  driver.findElement(By.xpath("//div[contains(@class, 'value test')]"));
  

• Match 1, 2, 3 and 4 (as long as elements have class value and test)

  driver.findElement(By.xpath("//div[contains(@class, 'value') and contains(@class, 'test')]"));
  

Also, in cases like this, Css Selector is always in favor of XPath (fast, concise, native).

• Match 1

  driver.findElement(By.cssSelector("div[class='value test']"));
  

• Match 1, 2 and 3

  driver.findElement(By.cssSelector("div[class*='value test']"));
  

• Match 1, 2, 3 and 4

  driver.findElement(By.cssSelector("div.value.test"));
  

When using multiple class names for the same tag within a CSS Selector, they must be separated by a dot instead of a space. Here's the correct way to express your third one:

(By.CSS_SELECTOR, ".ui.dropdown.selection")

OR

(By.CSS_SELECTOR, "div.ui.dropdown.selection").

As for the fourth one, you can't use By.CLASS_NAME with multiple class name components. You would have to pick one, but since that probably won't give you a unique selector, you'll be better off using one of the other ways to form a selector.

This By.classname("btn btn-xs btn-custom") will not work, as it contains multiple spaces which means it is combination of 3 classes.

You will have to switch to css selector or xpath , I do not know why you have mentioned that you do not want to use both of them.

However, If you are interest to use css selector :

You can try this :

By.cssSelector("btn.btn-xs.btn-custom")  

If you go by precedence :

1. ID
2. name
3. classname
4. linkText
5. partialLinkText
6. tagName
7. css selector
8. xpath