Something like this?
>>> st = "hello world"
>>> ' '.join(format(ord(x), 'b') for x in st)
'1101000 1100101 1101100 1101100 1101111 100000 1110111 1101111 1110010 1101100 1100100'
#using `bytearray`
>>> ' '.join(format(x, 'b') for x in bytearray(st, 'utf-8'))
'1101000 1100101 1101100 1101100 1101111 100000 1110111 1101111 1110010 1101100 1100100'
Answer from Ashwini Chaudhary on Stack OverflowSomething like this?
>>> st = "hello world"
>>> ' '.join(format(ord(x), 'b') for x in st)
'1101000 1100101 1101100 1101100 1101111 100000 1110111 1101111 1110010 1101100 1100100'
#using `bytearray`
>>> ' '.join(format(x, 'b') for x in bytearray(st, 'utf-8'))
'1101000 1100101 1101100 1101100 1101111 100000 1110111 1101111 1110010 1101100 1100100'
If by binary you mean bytes type, you can just use encode method of the string object that encodes your string as a bytes object using the passed encoding type. You just need to make sure you pass a proper encoding to encode function.
In [9]: "hello world".encode('ascii')
Out[9]: b'hello world'
In [10]: byte_obj = "hello world".encode('ascii')
In [11]: byte_obj
Out[11]: b'hello world'
In [12]: byte_obj[0]
Out[12]: 104
Otherwise, if you want them in form of zeros and ones --binary representation-- as a more pythonic way you can first convert your string to byte array then use bin function within map :
>>> st = "hello world"
>>> map(bin,bytearray(st))
['0b1101000', '0b1100101', '0b1101100', '0b1101100', '0b1101111', '0b100000', '0b1110111', '0b1101111', '0b1110010', '0b1101100', '0b1100100']
Or you can join it:
>>> ' '.join(map(bin,bytearray(st)))
'0b1101000 0b1100101 0b1101100 0b1101100 0b1101111 0b100000 0b1110111 0b1101111 0b1110010 0b1101100 0b1100100'
Note that in python3 you need to specify an encoding for bytearray function :
>>> ' '.join(map(bin,bytearray(st,'utf8')))
'0b1101000 0b1100101 0b1101100 0b1101100 0b1101111 0b100000 0b1110111 0b1101111 0b1110010 0b1101100 0b1100100'
You can also use binascii module in python 2:
>>> import binascii
>>> bin(int(binascii.hexlify(st),16))
'0b110100001100101011011000110110001101111001000000111011101101111011100100110110001100100'
hexlify return the hexadecimal representation of the binary data then you can convert to int by specifying 16 as its base then convert it to binary with bin.
Convert int to binary string in Python - Stack Overflow
python - How to convert 'binary string' to normal string in Python3? - Stack Overflow
how do i convert string to binary string and the reverse too?
String to binary
is there any proper method to convert a string in utf-8 encoded formant to binary string format and the reverse too. like example
data = "this string".encode("utf-8")
data = func(data)
print(data) #want to have a string as output like "0101010101111010101010......."
I want a function that takes for example 'Hello brother! ๐'(a combination of any unicode symbols) as input and outputs the binary equivalent using utf-8 so here:
'01001000 01100101 01101100 01101100 01101111 00100000 01100010 01110010 01101111 01110100 01101000 01100101 01110010 00100001 00100000 11110000 10011111 10011000 10001010'
The output should also be a string.