Python
docs.python.org › 3 › library › urllib.parse.html
urllib.parse — Parse URLs into components — Python 3.14.6 ...
The resulting string is a series of key=value pairs separated by '&' characters, where both key and value are quoted using the quote_via function. By default, quote_plus() is used to quote the values, which means spaces are quoted as a '+' character and ‘/’ characters are encoded as /, which follows the standard for GET requests (application/x-www-form-urlencoded).
Reddit
reddit.com › r/learnpython › encode url including slashes?
r/learnpython on Reddit: Encode url including slashes?
October 1, 2022 -
Hello i would like to encode an url like this:
http://www.foodserv.co.za
I tried it with the following code
import urllib link = urllib.parse.quote(link) print(link)
But with that i only get: http%3A//www.foodserv.co.za
But i would like to have also the // encoded and in the end i should look like this: http%3A%2F%2Fwww.foodserv.co.za
Is there some other way or parameter to encode the url like i need it?
Top answer 1 of 3
3
urllib.parse.quote_plus is what you want.
2 of 3
1
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GitHub
github.com › pallets › jinja › issues › 515
urlencode doesn't escape slashes · Issue #515 · pallets/jinja
November 20, 2015 - This was raised in #444, but this code always evaluates to b'/' on Python 3.4.1, so slashes still not escaped.
Author pallets
ProxiesAPI
proxiesapi.com › articles › encoding-urls-in-python-with-urllib
Encoding URLs in Python with urllib | ProxiesAPI
For the full URL, we want to leave the forward slashes unencoded. When building URLs in code, it's best to encode each component as you construct the full URL. For example: ... from urllib.parse import urlencode base = "https://www.example.com" path = "/my path" query = {"foo": "bar"} path = quote(path) query = urlencode(query) full_url = base + path + "?" + query
URL Encoder
urlencoder.io › python
How to encode URLs in Python | URLEncoder
>>> import urllib.parse >>> params = {'name': 'Rajeev Singh', 'phone': ['+919999999999', '+628888888888']} >>> urllib.parse.urlencode(params, doseq=True) 'name=Rajeev+Singh&phone=+919999999999&phone=+628888888888' In Python 2.x the quote(), quote_plus(), and urlencode() functions can be accessed directly from the urllib package.
URL Encode
urlencoder.org › enc › python
URL Encoding of "python" - Online
Reserved characters are characters that sometimes have special meaning. For example, forward slash characters are used to separate different parts of a URL (or more generally, a URI).
Django
code.djangoproject.com › ticket › 22589
#22589 (url reverse should encode forward slashes) – Django
Here, page.title is a completely free-form string that might contain any characters, including forward slashes. I want to encode it completely. The current url reverse() code will quote any parameters using Django's urlquote, which will call Python's quote, which will encode all special characters, except the slash (and _.-).
Top answer 1 of 2
10
From the Django source, urlencode is basically a wrapper around Django's urlquote utility method. From the comments in the source, urlquote is a UTF-8-safe version of urllib.quote.
So urlencode is using the same defaults as python's urllib.quote, and the reason that urllib.quote does not escape slashes can be found in the documentation:
Replace special characters in string using the %xx escape. Letters, digits, and the characters '_.-' are never quoted. By default, this function is intended for quoting the path section of the URL. The optional safe parameter specifies additional characters that should not be quoted — its default value is '/'.
So, the reason is that it's escaping the path, and '/' is a perfectly expected and valid character within a path.
2 of 2
2
To get urlencode to also escape / in a Django template, use {{ variable|urlencode:'' }}.
Explanation: The extra optional parameter tells urlencode the set of characters that are "safe", where the default is '/', so passing an empty string is telling urlencode that / is not safe and should be encoded.
DaniWeb
daniweb.com › programming › software-development › threads › 192290 › passing-variables-via-url-with-slashes
python - Passing variables via url with slashes | DaniWeb
May 15, 2009 - As Scru said, if you're trying to pass the values as a GET, you need to URLencode the string containing the date. If you feel some overwhelming need to do this manually, the URL encoding for a forward slash is '/'. Thus, it would look like this:
MojoAuth
mojoauth.com › binary-encoding-decoding › percent-encoding-url-encoding-with-python
Percent-encoding (URL Encoding) with Python | Binary Encoding Techniques Across Programming Languages
A common pitfall is failing to encode reserved characters such as /, ?, &, =, or # when they are intended as literal data, not as structural components of the URL. This can corrupt the URL's intended meaning. Always encode these characters if they are part of your data. Python's urllib.parse.quote() function handles this reliably.
PyTutorial
pytutorial.com › url-encoding-in-python-a-complete-guide
PyTutorial | URL Encoding in Python: A Complete Guide
January 28, 2026 - The slash remains. The space is encoded to . This is very useful for building complex URLs piece by piece. Query strings are a common part of URLs. They come after the question mark (?). Parameters are key-value pairs separated by ampersands (&). Encoding these manually with quote() is tedious and error-prone. The urllib.parse.urlencode() function is designed for this.
ProxiesAPI
proxiesapi.com › articles › handling-url-encoding-in-python-requests
Handling URL Encoding in Python Requests | ProxiesAPI
March 2, 2024 - quote_plus function from Python's ... The ampersand is the most common issue, but quote_plus can also handle encoding other special characters like spaces, slashes etc....
pytz
pythonhosted.org › percentcoding
percentcoding - fast url encoding and decoding
This is not surprising; the standard ... are pure Python. $ ./benchmark.py percentcodec.encode x 10000 0.348151922226 percentcodec.decode x 10000 0.381587028503 urllib.quote x 10000 4.51035284996 urllib.unquote x 10000 3.50923490524 ... All ASCII characters not occurring in the safe set are considered unsafe and will be escaped by encode. With quote and unquote, the '+' character does not map to a space, as is necessary for processing application/x-www-form-urlencoded...
GitHub
github.com › pallets › flask › issues › 2507
Percent encoded forward slash is stil treated as a URL component delimiter · Issue #2507 · pallets/flask
October 28, 2017 - Python version: Python 3.5.3 · ... /<string:company>/<string:user>. Company names and users would have to have the slash character disallowed otherwise they would not be able to be cleanly represented as a URL....
Author pallets
Python
bugs.python.org › issue13866
Issue 13866: {urllib,urllib.parse}.urlencode should not use quote_plus - Python tracker
January 25, 2012 - This issue tracker has been migrated to GitHub, and is currently read-only. For more information, see the GitHub FAQs in the Python's Developer Guide · This issue has been migrated to GitHub: https://github.com/python/cpython/issues/58074
SSOJet
ssojet.com › escaping › url-escaping-in-python
URL Escaping in Python | Escaping Techniques in Programming
Learn URL escaping in Python. Properly encode special characters for web requests and avoid errors. Master `urllib.parse` for reliable data transmission.
SEO North
seonorth.ca › seo north › server › how do you pass a slash in a url query string?
How do you pass a slash in a URL query string? - SEO North
March 25, 2026 - Here’s how you can encode slashes: let value = "example/data"; let encodedValue = encodeURIComponent(value); import urllib.parse · value = "example/data" encodedValue = urllib.parse.quote_plus(value) import java.net.URLEncoder; String value = "example/data"; String encodedValue = URLEncoder.encode(value, "UTF-8"); $value = "example/data"; $encodedValue = urlencode($value); These functions simplify encoding, ensuring special characters are correctly represented for seamless server communication.
Read the Docs
python.readthedocs.io › en › latest › library › urllib.parse.html
21.8. urllib.parse — Parse URLs into components
November 15, 2017 - The resulting string is a series of key=value pairs separated by '&' characters, where both key and value are quoted using the quote_via function. By default, quote_plus() is used to quote the values, which means spaces are quoted as a '+' character and ‘/’ characters are encoded as /, which follows the standard for GET requests (application/x-www-form-urlencoded).
SaltyCrane
saltycrane.com › blog › 2008 › 10 › how-escape-percent-encode-url-python
How to escape (percent-encode) a URL with Python - SaltyCrane Blog
October 29, 2008 - But for simple escaping, only quote_plus, or possibly quote is needed. I believe this is the appropriate solution to Python urlencode annoyance and O'Reilly's Amazon Hack #92.
GitHub
github.com › fastapi › fastapi › issues › 791
URL slash encoded · Issue #791 · fastapi/fastapi
December 14, 2019 - Describe the bug FastAPI is not routing URL containing slash encoded. To Reproduce Create a file with: from fastapi import FastAPI app = FastAPI() @app.get("/units/{unit}") def read_unit(unit: str): return {"unit": unit} Open the browser...
Author fastapi