Change the last line to:

temp = temp.append(data, ignore_index = True)

The reason we have to do this is because the append doesn't happen in place. The append method does not modify the data frame. It just returns a new data frame with the result of the append operation.

Edit:

Since writing this answer I have learned that you should never use DataFrame.append inside a loop because it leads to quadratic copying (see this answer).

What you should do instead is first create a list of data frames and then use pd.concat to concatenate them all in a single operation. Like this:

dfs = [] # an empty list to store the data frames
for file in file_list:
    data = pd.read_json(file, lines=True) # read data frame from json file
    dfs.append(data) # append the data frame to the list

temp = pd.concat(dfs, ignore_index=True) # concatenate all the data frames in the list.

This alternative should be considerably faster.

Note: Line separated json is now supported in read_json (since 0.19.0):

In [31]: pd.read_json('{"a":1,"b":2}\n{"a":3,"b":4}', lines=True)
Out[31]:
   a  b
0  1  2
1  3  4

or with a file/filepath rather than a json string:

pd.read_json(json_file, lines=True)

It's going to depend on the size of you DataFrames which is faster, but another option is to use str.join to smash your multi line "JSON" (Note: it's not valid json), into valid json and use read_json:

In [11]: '[%s]' % ','.join(test.splitlines())
Out[11]: '[{"a":1,"b":2},{"a":3,"b":4}]'

For this tiny example this is slower, if around 100 it's the similar, signicant gains if it's larger...

In [21]: %timeit pd.read_json('[%s]' % ','.join(test.splitlines()))
1000 loops, best of 3: 977 µs per loop

In [22]: %timeit l=[ json.loads(l) for l in test.splitlines()]; df = pd.DataFrame(l)
1000 loops, best of 3: 282 µs per loop

In [23]: test_100 = '\n'.join([test] * 100)

In [24]: %timeit pd.read_json('[%s]' % ','.join(test_100.splitlines()))
1000 loops, best of 3: 1.25 ms per loop

In [25]: %timeit l = [json.loads(l) for l in test_100.splitlines()]; df = pd.DataFrame(l)
1000 loops, best of 3: 1.25 ms per loop

In [26]: test_1000 = '\n'.join([test] * 1000)

In [27]: %timeit l = [json.loads(l) for l in test_1000.splitlines()]; df = pd.DataFrame(l)
100 loops, best of 3: 9.78 ms per loop

In [28]: %timeit pd.read_json('[%s]' % ','.join(test_1000.splitlines()))
100 loops, best of 3: 3.36 ms per loop

Note: of that time the join is surprisingly fast.

This code is affecting your outcome because your dataframe only has two rows:

df['name'] = [x[0]['name'] for x in df['region']]

I changed it to:

filename = '20191111.json'
df1=pd.read_json(filename)
df1 = df1.drop(columns=['info1', 'info2'])  

df2 = pd.DataFrame(columns=['name', 'date'])
names=[]
dates=[]
for x in df1['region']: 
   for name in x: 
     names.append(name['name']) 
     dates.append(filename)
df2['name']=names
df2['date']=dates 

and i get the correct data. you list comprehension can't add more rows than you already are in the data frame, so i created a new one.

One option is listing all files in a directory with os.listdir and then finding only those that end in '.json':

import os, json
import pandas as pd

path_to_json = 'somedir/'
json_files = [pos_json for pos_json in os.listdir(path_to_json) if pos_json.endswith('.json')]
print(json_files)  # for me this prints ['foo.json']

Now you can use pandas DataFrame.from_dict to read in the json (a python dictionary at this point) to a pandas dataframe:

montreal_json = pd.DataFrame.from_dict(many_jsons[0])
print montreal_json['features'][0]['geometry']

Prints:

{u'type': u'Point', u'coordinates': [-73.6051013, 45.5115944]}

In this case I had appended some jsons to a list many_jsons. The first json in my list is actually a geojson with some geo data on Montreal. I'm familiar with the content already so I print out the 'geometry' which gives me the lon/lat of Montreal.

The following code sums up everything above:

import os, json
import pandas as pd

# this finds our json files
path_to_json = 'json/'
json_files = [pos_json for pos_json in os.listdir(path_to_json) if pos_json.endswith('.json')]

# here I define my pandas Dataframe with the columns I want to get from the json
jsons_data = pd.DataFrame(columns=['country', 'city', 'long/lat'])

# we need both the json and an index number so use enumerate()
for index, js in enumerate(json_files):
    with open(os.path.join(path_to_json, js)) as json_file:
        json_text = json.load(json_file)

        # here you need to know the layout of your json and each json has to have
        # the same structure (obviously not the structure I have here)
        country = json_text['features'][0]['properties']['country']
        city = json_text['features'][0]['properties']['name']
        lonlat = json_text['features'][0]['geometry']['coordinates']
        # here I push a list of data into a pandas DataFrame at row given by 'index'
        jsons_data.loc[index] = [country, city, lonlat]

# now that we have the pertinent json data in our DataFrame let's look at it
print(jsons_data)

for me this prints:

  country           city                   long/lat
0  Canada  Montreal city  [-73.6051013, 45.5115944]
1  Canada        Toronto  [-79.3849008, 43.6529206]

It may be helpful to know that for this code I had two geojsons in a directory name 'json'. Each json had the following structure:

{"features":
[{"properties":
{"osm_key":"boundary","extent":
[-73.9729016,45.7047897,-73.4734865,45.4100756],
"name":"Montreal city","state":"Quebec","osm_id":1634158,
"osm_type":"R","osm_value":"administrative","country":"Canada"},
"type":"Feature","geometry":
{"type":"Point","coordinates":
[-73.6051013,45.5115944]}}],
"type":"FeatureCollection"}

You can use the method os.listdir("relative path to where the folders are") (take a look at the domumentation) to get all subdirectories in the cwd. And you should not use loads for getting the contents of a file, instead pass the file object to the json.load() method. Implementing it in your code would be something like this:

import os

for i in os.listdir(path) :
   new_file = path + i + file
   my_file = open(new_file,"r")
   obj = json.load(my_file)
   my_file.close()