InDesign uses Perl-compatible regular expressions (pcre). Getting a Unicode character into the replacement string is done by \x{XXXX} where XXXX is the hexadecimal character code:
2\x{2009}$5
But in general you can replace by any character you can type. Just put actual thin spaces into your search-and-replace dialog:
3 $5
You can use your OS's utilities to grab the thin space from the list of available characters, for Windows it's the "Character Map" tool, where the thin space can be found in the "General Punctuation" Unicode sub-range. Searching for "thin space" works as well. MacOS has the "Character Viewer", which can do the same thing.

Adapted from Semplice, following link from here.
[^\x00-\x80] matches any character not in the ASCII range.
Note that some of the characters may not be encoded correctly from the copy and paste.
var latin_map = 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function embolden( str, chr ){
return str.replace( /[^\x00-\x80]/g,
function (a) {
return chr == latin_map[a] ? '<b>' + a + '</b>' : a;
}
);
}
embolden( 'ádám', 'a' ); // "<b>á</b>d<b>á</b>m"
I've tried this code, see if it's what you're looking for:
'ádám'.replace(/./g,function(char){
switch(char.toLowerCase()){
case 'á':
case 'à':
case 'â':
case 'ã':
return '*';
break;
}
return char;
});
EDIT:
To replace all chars that don't belong to the ASCII table, just check if the char has a char code up to 127, since the ASCII table char codes are defined between 0 and 127 (notice that á doesn't belong to the Unicode table, but to the Extended ASCII table, that comes from 0 up to 255):
'ádám'.replace(/./g,function(char){
return char.charCodeAt(0)<=127 ? char : '<b>' + char + '</b>';
});
find and replace unicode by regex
c# - Replace Unicode character "�" with a space - Stack Overflow
Regex fails if the source string contains the Unicode replacement character
[Word] Insert Unicode character in RegExp.replace string
i have several strings of characters that have unicode at the end of them. I would like to do a find with regex and replace the unicode with the specified characters.
30May19Bel© 13Jun18Bel¬ 24Aug17Sar«
I would like to do a find and replace with regex
for example [0-9]{2}[a-zA-Z]{3}[0-9]{2}[a-zA-Z]{3}©
$path = 'C:temp\uni.txt'
$original_file = C:temp\uni.txt"
$destination_file = "C:temp\update.txt"
(Get-Content $original_file) | Foreach-Object {
$_ -replace '¨', '1'`
-replace '©', '2'`
-replace 'ª', '3'`
-replace '«', '4'`
-replace '¬', '5'`
-replace '°', '6'`
} | Set-Content $destination_fileand replace it with
30May19Bel2 13Jun18Bel5 24Aug17Sar4
This may be a caveman approach, and I know nothing about regex. If there is a better way, i am unaware of it, but totally open to someone dropping the egg of knowledge on me. It just seemed like the easiest way was to create a Rosetta Stone of sorts. Thanks, Rogue
Using String.Replace:
Use a simple String.Replace().
I've assumed that the only characters you want to remove are the ones you've mentioned in the question: � and you want to replace them by a normal space.
string text = "imp�ortant";
string cleaned = text.Replace('\u00ef', ' ')
.Replace('\u00bf', ' ')
.Replace('\u00bd', ' ');
// Returns 'imp ortant'
Or using Regex.Replace:
string cleaned = Regex.Replace(text, "[\u00ef\u00bf\u00bd]", " ");
// Returns 'imp ortant'
Try it out: Dotnet Fiddle
Define a range of ASCII characters, and replace anything that is not within that range.
We want to find only Unicode characters, so we will match on a Unicode character and replace.
Regex.Replace("This is my te\uFFFDxt from csv file", @"[^\u0000-\u007F]+", " ")
The above pattern will match anything that is not ^ in the set [ ] of this range \u0000-\u007F (ASCII characters (everything past \u007F is Unicode)) and replace it with a space.
Result
This is my te xt from csv file
You can adjust the range provided \u0000-\u007F as needed to expand the range of allowed characters to suit your needs.
So my regex pretty much matches what it needs to (I hope), but now I'd like to make replacements that insert certain special characters. As an example, I'd like to insert a narrow non-breaking space (\u202F) between a number and its unit. The number and the unit are already being captured in their respective capture group, so now I only need to create the correct replacement string.
I kinda expected "$1\u202F$2" to work, but unfortunately that just prints out silliness like 200\u202Fm.
I also tried "$1" & Chr(8239) & "$2", which compiled, but did literally nothing.
Remove the regular space that you have first in the pattern:
str = str.replace(/[\u00A0\u1680\u180e\u2000-\u2009\u200a\u200b\u202f\u205f\u3000]/g,'');
try this:
var str = "Hello this is a test of the site";
str= str.replace(/[\u00A0\u1680\u180e\u2000-\u2009\u200a\u200b\u202f\u205f\u3000]/g,'')
same as you did, but with out ' ' (regular space)
Decode the string to Unicode. Assuming it's UTF-8-encoded:
str.decode("utf-8")Call the
replacemethod and be sure to pass it a Unicode string as its first argument:str.decode("utf-8").replace(u"\u2022", "*")Encode back to UTF-8, if needed:
str.decode("utf-8").replace(u"\u2022", "*").encode("utf-8")
(Fortunately, Python 3 puts a stop to this mess. Step 3 should really only be performed just prior to I/O. Also, mind you that calling a string str shadows the built-in type str.)
Encode string as unicode.
>>> special = u"\u2022"
>>> abc = u'ABC•def'
>>> abc.replace(special,'X')
u'ABCXdef'