Here is your answer:

    String regex = "(?<=[\\d])(,)(?=[\\d])";
    Pattern p = Pattern.compile(regex);
    String str = "Your input";
    Matcher m = p.matcher(str);
    str = m.replaceAll("");
    System.out.println(str);

This only affects NUMBERS, not strings, as you asked.

Try adding that in your main method. Or try this one, it receives input:

       String regex = "(?<=[\\d])(,)(?=[\\d])";
        Pattern p = Pattern.compile(regex);
        System.out.println("Value?: ");
            Scanner scanIn = new Scanner(System.in);
            String str = scanIn.next();
        Matcher m = p.matcher(str);
        str = m.replaceAll("");
        System.out.println(str);

 public static void main(String args[]) throws IOException

    {

        String regex = "(?<=[\\d])(,)(?=[\\d])";
        Pattern p = Pattern.compile(regex);
        String str = "John loves cakes and he always orders them by dialing \"989,444 1234\". Johns credentials are as follows\" \"Name\":\"John\", \"Jr\", \"Mobile\":\"945,234,1110\"";
        Matcher m = p.matcher(str);
        str = m.replaceAll("");
        System.out.println(str);
    }

Output

John loves cakes and he always orders them by dialing "989444 1234". Johns credentials are as follows" "Name":"John", "Jr", "Mobile":"9452341110"

do like this

NumberFormat format = NumberFormat.getCurrencyInstance();
Number number = format.parse("\$123,456.78");
System.out.println(number.toString());

output

123456.78

You have a DecimalFormat which you're using to format the value. Use the same object to parse the value, instead of using Double.valueOf.

Additionally:

• Try to avoid formatting/parsing cycles where possible. Keep the value as a number for almost your whole code base, only formatting for presentation and only parsing for user input
• Don't use double for currency values; use BigDecimal which will reduce the surprises you get when it comes to "inaccurate" arithmetic
• Follow Java naming conventions wherever possible. StrCash_price_deal is horrible in both casing and underscore-ness

Is this comma a decimal separator or are these two numbers? In the first case you must provide Locale to NumberFormat class that uses comma as decimal separator:

NumberFormat.getNumberInstance(Locale.FRANCE).parse("265,858")

This results in 265.858. But using US locale you'll get 265858:

NumberFormat.getNumberInstance(java.util.Locale.US).parse("265,858")

That's because in France they treat comma as decimal separator while in US - as grouping (thousand) separator.

If these are two numbers - String.split() them and parse two separate strings independently.

class Removal · { · public static void main(String args[]) · String str1=new String("Rs. 30,000"); · String str2=new String("30000"); · String string1=""; · //lets us first remove irrelevant data from str1 · int ch;    // This is used to typecast the character to integer value(ASCII value of a character).  · for(int i=0;i=48)   // 0 is represented as 48    and    9 is represented as 57 in ASCII · string1=string1+str1.charAt(i);   // concatenation of number · } ·   · // our final aim to compare  · if(string1.equals(str2)) · System.out.println("True"); · else · System.out.println("False");

You can modify the loop

for(int i = 0; i < numbers.length - 1; i++) {
  System.out.print(numbers[i] + ",");
}
System.out.print(numbers[numbers.length - 1]);

Or use streams

 Arrays.stream(numbers).collect(Collectors.joining(","));

It seems that you are looking for modulo (reminder) operator %. Also there is no "after comma value" in integers words so 184 / 60 = 3 not 3.06666.

int time = 184;
int minutes = time / 60;
int seconds = time % 60;
System.out.println(minutes + " minutes : " + seconds + " seconds");

Output: 3 minutes : 4 seconds

---

You can also use Period from JodaTime library.

int time = 184;
Period period = new Period(time * 1000);//in milliseconds 

System.out.printf("%d minutes, %d seconds%n", period.getMinutes(),
        period.getSeconds());

which will print 3 minutes, 4 seconds.

I am writing a program to clean up a list of cells that I exported from excel as a .csv. The output I am currently getting results in: "[Email: mcs7yh,@xxxxx.edu, Email: pg2bn,@xxxxx.edu, Email: jtt5pj,@xxxxx.edu, Email: tww6ar,@xxxxx.edu, .... continued". I would like to remove the comma before the @ symbol, as well as the "Email: " section from each element in the array. Any ideas on how this could be done?