>>> def rreplace(s, old, new, occurrence):
... li = s.rsplit(old, occurrence)
... return new.join(li)
...
>>> s
'1232425'
>>> rreplace(s, '2', ' ', 2)
'123 4 5'
>>> rreplace(s, '2', ' ', 3)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 4)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 0)
'1232425'
Top answer 1 of 8
274
>>> def rreplace(s, old, new, occurrence):
... li = s.rsplit(old, occurrence)
... return new.join(li)
...
>>> s
'1232425'
>>> rreplace(s, '2', ' ', 2)
'123 4 5'
>>> rreplace(s, '2', ' ', 3)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 4)
'1 3 4 5'
>>> rreplace(s, '2', ' ', 0)
'1232425'
2 of 8
118
Here is a one-liner:
result = new.join(s.rsplit(old, maxreplace))
Return a copy of string s with all occurrences of substring old replaced by new. The first maxreplace occurrences are replaced.
and a full example of this in use:
s = 'mississipi'
old = 'iss'
new = 'XXX'
maxreplace = 1
result = new.join(s.rsplit(old, maxreplace))
>>> result
'missXXXipi'
ItSolutionstuff
itsolutionstuff.com › post › python-replace-last-occurrence-in-string-exampleexample.html
Python Replace Last Occurrence in String Example - ItSolutionstuff.com
October 30, 2023 - Then we will use replace() function to replace last occurrence from string in python. So, without further ado, let's see simple examples: You can use these examples with python3 (Python 3) version.
Remove Last Occurrence of Letter
You could have used rfind() and string slicing, like this: def removeLetter(string,letter): i = string.rfind(letter) return string[1:] if i==-1 else string[:i]+string[i+1:] That's less about overcomplicating, and more about just not knowing that you could do that yet. You'll learn new techniques the more you code, so keep at it! Another thought: Write a function that removes the last occurence*[sic]* of a given letter in a given string. If the given letter does not appear in the string then remove the first letter of that string. Were you supposed to return the modified string, or just print it? def removeLetter(string,letter): i = string.rfind(letter) print( string[1:] if i==-1 else string[:i]+string[i+1:] ) More on reddit.com
8
2
February 4, 2021python - Finding last occurrence of substring in string, replacing that - Stack Overflow
So I have a long list of strings in the same format, and I want to find the last "." character in each one, and replace it with ". - ". I've tried using rfind, but I can't seem to utilize it proper... More on stackoverflow.com
python - Which method is faster for replacing the last occurrence of a substring in a string? - Stack Overflow
I have a string which is a combination of "S"s and "C"s. There is at least one occurrence of each. I want to find the last occurrence of "CS" and change it to "SC". I have two methods (so far): ... More on stackoverflow.com
python - To replace but the last occurrence of string in a text - Stack Overflow
Suppose I have this piece of text: Saturday and Sunday and Monday and Tuesday and Wednesday and Thursday and Friday are days of the week. I want all but the last and to be replaced with a comma: More on stackoverflow.com
Sarathlal
sarathlal.com › replace-last-occurrence-of-character-in-string-python
Find and replace last occurrence of a character in string - Python - Sarathlal N
September 15, 2016 - old_string = "MK-36-W-357-IJO-36-MDR" k = old_string.rfind("-") new_string = old_string[:k] + "." + old_string[k+1:] print(new_string) #Result will be MK-36-W-357-IJO-36.MDR
Bobby Hadz
bobbyhadz.com › blog › python-replace-last-occurrence-of-substring-in-string
Replace the Last or Nth occurrence in String in Python | bobbyhadz
April 9, 2024 - Use the str.rfind() method to get the index of the last occurrence of the substring. Use string slicing to replace the last occurrence of the substring in the string.
Bobby Hadz
bobbyhadz.com › blog › python-replace-last-character-in-string
Replace the Last or Last N characters in a String in Python | bobbyhadz
April 9, 2024 - Use string slicing to replace the last character in a string, e.g. `my_str[:-1] + '_'`.
TutorialsPoint
tutorialspoint.com › article › how-to-replace-the-last-occurrence-of-an-expression-in-a-string-in-python
How to replace the last occurrence of an expression in a string in Python?
March 24, 2026 - The rsplit() method splits the string into a list of substrings, starting from the right end. By limiting the split to 1 occurrence, we can isolate the last occurrence and replace it using join().
ItSolutionstuff
itsolutionstuff.com › post › python-replace-last-character-occurrence-in-string-exampleexample.html
Python Replace Last Character Occurrence in String Example - ItSolutionstuff.com
October 30, 2023 - In this example, i will add myString variable with hello string. Then we will use join() and rsplit() function to replace last character occurrence from string in python.
Finxter
blog.finxter.com › home › learn python blog › replace last substring occurrence in python string
Replace Last Substring Occurrence in Python String - Be on the Right Side of Change
January 24, 2022 - You replace this rightmost pattern with the replacement string using the re.sub() method. You set the re.DOTALL flag to make sure that the dot and asterisk .* part of the pattern matches all characters including the newline character.
CodingTechRoom
codingtechroom.com › question › replace-last-occurrence-character-string-python
How to Replace the Last Occurrence of a Character in a String in Python? - CodingTechRoom
def replace_last_occurrence(text, char_to_replace, new_char): reversed_text = text[::-1] # Reverse the string modified_text = reversed_text.replace(char_to_replace[::-1], new_char, 1) # Replace once return modified_text[::-1] # Reverse back to original order # Example usage: result = replace_last_occurrence('hello world', 'o', 'a') # 'hella world' print(result) Using string methods incorrectly. Not accounting for string immutability in Python.
Reddit
reddit.com › r/learnpython › remove last occurrence of letter
r/learnpython on Reddit: Remove Last Occurrence of Letter
February 4, 2021 -
Hello everyone, I have a question about a problem that I actually have already solved. The task goes like this:
Write a function that removes the last occurence of a given letter in a given string. If the given letter does not appear in the string then remove the first letter of that string.
So in the code under the text you can see that I solved the task. I feel like I overcomplicated things. I don't know how I could simplify it. Any tips?
///Edit: probably should've noted that I cannot use rfind
def removeLetter(string,letter):
newWord = str()
index = 0
newString = str()
originalString = str()
for char in string:
newString = char + newString
for char in newString:
if char==letter:
index=newString.index(char)
newWord = newString[:index] + newString[(index+1):]
for char in newWord:
originalString = char + originalString
if letter not in string:
print(string[1:])
else:
print(originalString)
removeLetter("testing", "t") Top answer 1 of 4
2
You could have used rfind() and string slicing, like this: def removeLetter(string,letter): i = string.rfind(letter) return string[1:] if i==-1 else string[:i]+string[i+1:] That's less about overcomplicating, and more about just not knowing that you could do that yet. You'll learn new techniques the more you code, so keep at it! Another thought: Write a function that removes the last occurence*[sic]* of a given letter in a given string. If the given letter does not appear in the string then remove the first letter of that string. Were you supposed to return the modified string, or just print it? def removeLetter(string,letter): i = string.rfind(letter) print( string[1:] if i==-1 else string[:i]+string[i+1:] )
2 of 4
1
Are you aware the 3rd value in a slice is the increment? If I was going to code it the way you did, I'd use reverse increment slice to reverse it instead of your loops like so: def removeLetter(string, letter): idx = 0 newString = string[::-1] for char in newString: if char == letter: idx = newString.index(char) newWord = newString[:idx] + newString[(idx + 1):] originalString = newWord[::-1] if letter not in string: print(string[1:]) else: print(originalString) removeLetter("testing", "t") (Removed the unnecessarily string definitions).
pythontutorials
pythontutorials.net › blog › how-to-replace-some-characters-from-the-end-of-a-string
How to Replace the Last Occurrence of a Character in a Python String: Built-in Methods & Examples — pythontutorials.net
String manipulation is a cornerstone of programming, and Python offers a rich set of tools to handle strings. One common task you might encounter is replacing the **last occurrence** of a specific character (or substring) in a string. Unlike replacing all occurrences (via `str.replace()`) or the first occurrence (via slicing), Python does not have a built-in method like `str.replace_last()` to handle this directly.
GitHub
github.com › bobbyhadz › python-replace-last-occurrence-of-substring-in-string › blob › main › main.py
python-replace-last-occurrence-of-substring-in-string/main.py at main · bobbyhadz/python-replace-last-occurrence-of-substring-in-string
# Replace the Last occurrence of Substring in String in Python
Author: bobbyhadz
Tutorial Reference
tutorialreference.com › python › examples › faq › python-how-to-replace-last-n-characters-in-a-string
How to Replace Last Character or Last N Characters in a String in Python | Tutorial Reference
... This is useful if you need the separator itself or want to handle the "not found" case differently. You manually reconstruct the string using concatenation (+). To replace the single last character OR the last N characters by position: Use string slicing my_str[:-N] + replacement.
Python Examples
pythonexamples.org › python-string-replace-last-occurrence
Python String - Replace last occurrence
To replace only the last occurrence in a string in Python, you can use string replace() method with string reversal, or find the index of last occurrence of old string and replace it with the new string.
Top answer 1 of 7
169
This should do it
old_string = "this is going to have a full stop. some written sstuff!"
k = old_string.rfind(".")
new_string = old_string[:k] + ". - " + old_string[k+1:]
2 of 7
28
To replace from the right:
def replace_right(source, target, replacement, replacements=None):
return replacement.join(source.rsplit(target, replacements))
In use:
>>> replace_right("asd.asd.asd.", ".", ". -", 1)
'asd.asd.asd. -'
GitHub
github.com › bobbyhadz › python-replace-last-occurrence-of-substring-in-string
GitHub - bobbyhadz/python-replace-last-occurrence-of-substring-in-string: A repository for an article at https://bobbyhadz.com/blog/python-replace-last-occurrence-of-substring-in-string · GitHub
To run the code, issue the python main.py command.
Author: bobbyhadz
w3tutorials
w3tutorials.net › blog › replace-last-occurrence-of-a-character-in-a-string
How to Replace Last Occurrence of a Character in a String: Escaping the Last Double Quote Example — w3tutorials.net
Split the string into two parts: everything before the last occurrence, and everything after it. Concatenate these parts with the replacement string inserted in place of the target character. Python provides built-in tools to simplify this workflow.
Top answer 1 of 2
8
This is one way:
>>> s = 'CSsomethingSCSagainCSsomething'
>>> 'SC'.join(s.rsplit('CS', 1))
CSsomethingSCSagainSCsomething
Syntax:
new_substring.join(str.rsplit(old_substring, occurance))
2 of 2
2
In my crude timing, this beats the rsplit() and join() solution by 20%:
head, _, tail = string.rpartition('CS')
new_string = f"{head}SC{tail}"
I does depend on Python 3.6+, of course.
Top answer 1 of 2
19
str.replace() method has a count argument:
str.replace(old, new[, count])Return a copy of the string with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced.
Then, use str.count() to check how many and in the string and then -1 (because you need the last and):
str.count(sub[, start[, end]])Return the number of non-overlapping occurrences of substring sub in the range
[start, end]. Optional arguments start and end are interpreted as in slice notation.
Demo:
>>> string = 'Saturday and Sunday and Monday and Tuesday and Wednesday and Thursday and Friday are days of the week.'
>>> string.replace(' and ', ", ", (string.count(' and ')-1))
'Saturday, Sunday, Monday, Tuesday, Wednesday, Thursday and Friday are days of the week. '
2 of 2
4
If you want a regex solution, you could match all the ands which are followed by another one later in the string.
>>> str='Monday and Tuesday and Wednesday and Thursday and Friday and Saturday and Sunday are the days of the week.'
>>> import re
>>> re.sub(' and (?=.* and )', ', ', str)
'Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday are the days of the week.'
(?=...) is a lookahead which makes sure there is a match later in the string without including it in the actual match (so also not in the substitution). It's sort of like a conditional on the match.