You can use DataFrame.fillna or Series.fillna which will replace the Python object None, not the string 'None'.

import pandas as pd
import numpy as np

For dataframe:

df = df.fillna(value=np.nan)

For column or series:

df.mycol.fillna(value=np.nan, inplace=True)

It's possible that it's actually holding the string "None" rather than the Python value of None. Try: df.replace("None","",inplace=True)

Actually in later versions of pandas this will give a TypeError:df.replace('-', None) TypeError: If "to_replace" and "value" are both None then regex must be a mappingYou can do it by passing either a list or a dictionary:In [11]: df.replace('-', df.replace(['-'], [None]) # or .replace('-', {0: None}) Out[11]: 0 0 None 1 3 2 2 3 5 4 1 5 -5 6 -1 7 None 8 9But I recommend using NaNs rather than None:In [12]: df.replace('-', np.nan) Out[12]: 0 0 NaN 1 3 2 2 3 5 4 1 5 -5 6 -1 7 NaN 8 9

Actually in later versions of pandas this will give a TypeError:

df.replace('-', None)
TypeError: If "to_replace" and "value" are both None then regex must be a mapping

You can do it by passing either a list or a dictionary:

In [11]: df.replace('-', df.replace(['-'], [None]) # or .replace('-', {0: None})
Out[11]:
      0
0  None
1     3
2     2
3     5
4     1
5    -5
6    -1
7  None
8     9

But I recommend using NaNs rather than None:

In [12]: df.replace('-', np.nan)
Out[12]:
     0
0  NaN
1    3
2    2
3    5
4    1
5   -5
6   -1
7  NaN
8    9

The simplest thing to do is just:

sala['N10'].replace('None', 'vcv', inplace=True)

that should work.

If they were true NaN values then calling fillna would've worked.

e.g.

sala['N10'].fillna(value='vcv', inplace = True)

also what I suggested in my comment:

sala.loc[sala['N10'].isnull(), 'N10'] = 'vcv'

This is sufficient

df.fillna("",inplace=True)

df
Out[142]: 
   A                    B  C  D  E
0  A  2014-01-02 02:00:00     A  1
1  B  2014-01-02 03:00:00  B  B  2
2     2014-01-02 04:00:00  C  C   
3  C                       C     4

edit 2021-07-26 complete response following @dWitty's comment

If you really want to keep Nat and NaN values on other than text, you just need fill Na for your text column In your exemple this is A, C, D

You just send a dict of replacement value for your columns. value can be differents for each column. For your case you just need construct the dict

# default values to replace NA (None)
# values = {"A": "", "C": "", "D": ""}
values = (dict([[e,""] for e in ['A','C','D']]))
df.fillna(value=values, inplace=True)

df
Out[142]: 
   A                   B  C  D    E
0  A 2014-01-02 02:00:00     A  1.0
1  B 2014-01-02 03:00:00  B  B  2.0
2    2014-01-02 04:00:00  C  C  NaN
3  C                 NaT  C     4.0