May 28, 2025 - #include <stdio.h> // Iterative function to // reverse digits of num int reverseDigits(int num) { int rev_num = 0; while (num > 0) { rev_num = rev_num * 10 + num % 10; num = num / 10; } return rev_num; } int main() { int num = 4562; printf("Given ...

Created with over a decade of experience and thousands of feedback. ... #include <stdio.h> int main() { int n, reverse = 0, remainder, original; printf("Enter an integer: "); scanf("%d", &n); original = n; while (n != 0) { remainder = n % 10; reverse = reverse * 10 + remainder; n /= 10; } if (original % 10 == 0) { printf("Reversed number = %d", reverse); while (original % 10 == 0) { printf("0"); original /= 10; } } else { printf("Reversed number = %d", reverse); } return 0; }

February 26, 2024 - While num > 0 // Loop until there are no more digits in num a. Extract the last digit of num: digit = num % 10 b. Append digit to rev_num: rev_num = rev_num * 10 + digit c. Remove the last digit from num: num = num / 10 · Return rev_num // rev_num now contains the reversed number

March 9, 2024 - In C, we can leverage recursion to reverse a number with just a few lines of code. The key is to continuously divide the number by 10, extract the last digit using the modulo operator, and accumulate it into the result.

September 28, 2022 - This C program accepts an integer and reverse it. ... #include<stdio.h> //main program int main () { //variables initialization int num, reverse = 0, rem; num=1234; printf("The number is: %d\n",num); //loop to find reverse number while(num != 0) { rem = num % 10; reverse = reverse * 10 + rem; num /= 10; }; //output printf("Reverse: %d\n",reverse); return 0; } // Time complexity O(N) // Space complexity : O(1)

Multiply the reversed number by 10 and add the extracted digit. Remove the last digit from the original number by dividing it by 10. Repeat steps 2 to 4 until the original number becomes 0. Return the reversed number. ... int reverseNumber(int n) { int reversed = 0; while (n != 0) { int digit ...

Reverse a number in C. GitHub Gist: instantly share code, notes, and snippets.

Problem Statement: Write a C Program to reverse number. Required Knowledge: C Input/Output, C Variables, C Datatypes, C while..loop

#include<stdio.h> main() { int n, reverse = 0; printf("Enter a number to reverse:\n"); scanf("%d",&n); while (n != 0) { reverse = reverse * 10; reverse = reverse + n; n = n/10; } printf("Reverse of entered number is = %d\n", reverse); } Email ThisBlogThis!Share to XShare to FacebookShare to ...

July 23, 2025 - Let us assume the number to be reversed is num and the reversed number will be stored in rev_num. Initialize rev_num = 0. Run a loop till num > 0. The rightmost digit of num can be obtained by performing modulo by 10 (num % 10).

April 5, 2025 - On each iteration, the reverse variable will collect the last digit of a number. #include <stdio.h> int rem, reverse = 0; int reverse_number(int Number) { if (Number > 0) { rem = Number % 10; reverse = reverse * 10 + rem; reverse_number (Number /10); } return reverse; } int main() { int number; printf("Please Enter any number to Reverse = "); scanf("%d", &number); reverse = reverse_number(number); printf("Reverse of entered number %d = %d\n", number, reverse); }

Reverse digits of a number. Complete C program with detailed explanation, step-by-step execution, and output.

July 15, 2018 - #include<stdio.h> void main() { int n,reverse=0; printf("Enter a number\n"); scanf("%d",&n); while(n!=0) { reverse=reverse*10+n; n=n/10; } printf("Reversed number = %d",reverse); } ... AI BAKKT Bentley Bitcoin bitcoin mining BITMAIN Blockchain ...

Initialize the reversed number to 0. While the number to be reversed is not equal to 0, do the following: Get the remainder of the number to be reversed when divided by 10. Multiply the reversed number by 10 and add the remainder to it. Divide the number to be reversed by 10.

Note that the exponent is written in decimal rather than hexadecimal, and that it gives the power of 2 by which to multiply the coefficient. For example, the hexadecimal string 0x3.a7p10 represents the floating-point number (3 + 10./16 + 7./16**2) * 2.0**10, or 3740.0: ... Applying the reverse conversion to 3740.0 gives a different hexadecimal string representing the same number:

January 2, 2021 - Get the last digit of the given number by performing the modulo division (%) and store the value in last_digit variable, likey last_digit= number % 10. Multiply reversed by 10 and add last_digit, like reversed = reversed*10 + last_digit.

The logic behind to implement this program - Input Number, and run a loop until number is greater than 0, using remainder (Modulus) operator extract last digits and then dividing by 10, last digits will be removed. This process will be executed until number is not zero.

February 28, 2021 - Output Enter a number:123456789 Reverse Number is:987654321 · Let’s now update the void rev_num(int number) method so that we can reverse a number using the while loop.

After all the iterations, the final reverse number will be saved in rev. ... //program name: Reverse_of_Number.c #include<stdio.h> int main() { int num,r,rev=0; printf("Enter a number to find reverse: "); scanf("%d",&num); while(num) { r=num; rev=rev*10+r; num=num/10; } printf("Reversed of given number: %d",rev); return 0; }