You could re-invent the wheel, as many other answers suggest. Alternately, you could use someone else's wheel -- I'd suggest Newlib's, which is BSD-licensed and intended for use on embedded systems. It properly handles negative numbers, NaNs, infinities, and cases which are not representable as integers (due to being too large), as well as doing so in an efficient manner that uses exponents and masking rather than generally-costlier floating-point operations. In addition, it's regularly tested, so you know it doesn't have glaring corner-case bugs in it.
The Newlib source can be a bit awkward to navigate, so here are the bits you want:
Float version: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=blob;f=newlib/libm/common/sf_round.c;hb=master
Double version: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=blob;f=newlib/libm/common/s_round.c;hb=master
Word-extraction macros defined here: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=blob;f=newlib/libm/common/fdlibm.h;hb=master
If you need other files from there, the parent directory is this one: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=tree;f=newlib/libm/common;hb=master
For the record, here's the code for the float version. As you can see, there's a bit of complexity required to deal with all the possible cases correctly.
float roundf(x)
{
int signbit;
__uint32_t w;
/* Most significant word, least significant word. */
int exponent_less_127;
GET_FLOAT_WORD(w, x);
/* Extract sign bit. */
signbit = w & 0x80000000;
/* Extract exponent field. */
exponent_less_127 = (int)((w & 0x7f800000) >> 23) - 127;
if (exponent_less_127 < 23)
{
if (exponent_less_127 < 0)
{
w &= 0x80000000;
if (exponent_less_127 == -1)
/* Result is +1.0 or -1.0. */
w |= ((__uint32_t)127 << 23);
}
else
{
unsigned int exponent_mask = 0x007fffff >> exponent_less_127;
if ((w & exponent_mask) == 0)
/* x has an integral value. */
return x;
w += 0x00400000 >> exponent_less_127;
w &= ~exponent_mask;
}
}
else
{
if (exponent_less_127 == 128)
/* x is NaN or infinite. */
return x + x;
else
return x;
}
SET_FLOAT_WORD(x, w);
return x;
}
math - Concise way to implement round() in C? - Stack Overflow
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Rounding in C
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You could re-invent the wheel, as many other answers suggest. Alternately, you could use someone else's wheel -- I'd suggest Newlib's, which is BSD-licensed and intended for use on embedded systems. It properly handles negative numbers, NaNs, infinities, and cases which are not representable as integers (due to being too large), as well as doing so in an efficient manner that uses exponents and masking rather than generally-costlier floating-point operations. In addition, it's regularly tested, so you know it doesn't have glaring corner-case bugs in it.
The Newlib source can be a bit awkward to navigate, so here are the bits you want:
Float version: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=blob;f=newlib/libm/common/sf_round.c;hb=master
Double version: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=blob;f=newlib/libm/common/s_round.c;hb=master
Word-extraction macros defined here: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=blob;f=newlib/libm/common/fdlibm.h;hb=master
If you need other files from there, the parent directory is this one: https://sourceware.org/git/gitweb.cgi?p=newlib-cygwin.git;a=tree;f=newlib/libm/common;hb=master
For the record, here's the code for the float version. As you can see, there's a bit of complexity required to deal with all the possible cases correctly.
float roundf(x)
{
int signbit;
__uint32_t w;
/* Most significant word, least significant word. */
int exponent_less_127;
GET_FLOAT_WORD(w, x);
/* Extract sign bit. */
signbit = w & 0x80000000;
/* Extract exponent field. */
exponent_less_127 = (int)((w & 0x7f800000) >> 23) - 127;
if (exponent_less_127 < 23)
{
if (exponent_less_127 < 0)
{
w &= 0x80000000;
if (exponent_less_127 == -1)
/* Result is +1.0 or -1.0. */
w |= ((__uint32_t)127 << 23);
}
else
{
unsigned int exponent_mask = 0x007fffff >> exponent_less_127;
if ((w & exponent_mask) == 0)
/* x has an integral value. */
return x;
w += 0x00400000 >> exponent_less_127;
w &= ~exponent_mask;
}
}
else
{
if (exponent_less_127 == 128)
/* x is NaN or infinite. */
return x + x;
else
return x;
}
SET_FLOAT_WORD(x, w);
return x;
}
int round(double x)
{
if (x < 0.0)
return (int)(x - 0.5);
else
return (int)(x + 0.5);
}
The wording in the man-page is meant to be read literally, that is in its mathematical sense. The wording "x is integral" means that x is an element of Z, not that x has the data type int.
Casting a double to int can be dangerous because the maximum arbitrary integral value a double can hold is 2^52 (assuming an IEEE 754 conforming binary64 ), the maximum value an int can hold might be smaller (it is mostly 32 bit on 32-bit architectures and also 32-bit on some 64-bit architectures).
If you need only powers of ten you can test it with this little program yourself:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(){
int i;
for(i = 0;i < 26;i++){
printf("%d:\t%.2f\t%d\n",i, pow(10,i), (int)pow(10,i));
}
exit(EXIT_SUCCESS);
}
Instead of casting you should use the functions that return a proper integral data type like e.g.: lround(3).
here is an excerpt from the man page.
#include <math.h>
double round(double x);
float roundf(float x);
long double roundl(long double x);
notice: the returned value is NEVER a integer. However, the fractional part of the returned value is set to 0.
notice: depending on exactly which function is called will determine the type of the returned value.
Here is an excerpt from the man page about which way the rounding will be done:
These functions round x to the nearest integer, but round halfway cases
away from zero (regardless of the current rounding direction, see
fenv(3)), instead of to the nearest even integer like rint(3).
For example, round(0.5) is 1.0, and round(-0.5) is -1.0.
I have a question when it comes to rounding in C. Does it round up or down at .5? If it does round up, then does that mean that the smallest value of k in the code below can only be 1?
int main()
{
int k = 13;
int i;
for (i = 0; i < 8; i++) {
printf("%d", (k%2));
k >>= 1;
}
printf("%n");
}