I was working with statistics in Java 2 years ago and I still got the codes of a function that allows you to round a number to the number of decimals that you want. Now you need two, but maybe you would like to try with 3 to compare results, and this function gives you this freedom.
/**
* Round to certain number of decimals
*
* @param d
* @param decimalPlace
* @return
*/
public static float round(float d, int decimalPlace) {
BigDecimal bd = new BigDecimal(Float.toString(d));
bd = bd.setScale(decimalPlace, BigDecimal.ROUND_HALF_UP);
return bd.floatValue();
}
You need to decide if you want to round up or down. In my sample code I am rounding up.
Hope it helps.
EDIT
If you want to preserve the number of decimals when they are zero (I guess it is just for displaying to the user) you just have to change the function type from float to BigDecimal, like this:
public static BigDecimal round(float d, int decimalPlace) {
BigDecimal bd = new BigDecimal(Float.toString(d));
bd = bd.setScale(decimalPlace, BigDecimal.ROUND_HALF_UP);
return bd;
}
And then call the function this way:
float x = 2.3f;
BigDecimal result;
result=round(x,2);
System.out.println(result);
This will print:
2.30
Answer from Jav_Rock on Stack OverflowI was working with statistics in Java 2 years ago and I still got the codes of a function that allows you to round a number to the number of decimals that you want. Now you need two, but maybe you would like to try with 3 to compare results, and this function gives you this freedom.
/**
* Round to certain number of decimals
*
* @param d
* @param decimalPlace
* @return
*/
public static float round(float d, int decimalPlace) {
BigDecimal bd = new BigDecimal(Float.toString(d));
bd = bd.setScale(decimalPlace, BigDecimal.ROUND_HALF_UP);
return bd.floatValue();
}
You need to decide if you want to round up or down. In my sample code I am rounding up.
Hope it helps.
EDIT
If you want to preserve the number of decimals when they are zero (I guess it is just for displaying to the user) you just have to change the function type from float to BigDecimal, like this:
public static BigDecimal round(float d, int decimalPlace) {
BigDecimal bd = new BigDecimal(Float.toString(d));
bd = bd.setScale(decimalPlace, BigDecimal.ROUND_HALF_UP);
return bd;
}
And then call the function this way:
float x = 2.3f;
BigDecimal result;
result=round(x,2);
System.out.println(result);
This will print:
2.30
Let's test 3 methods:
1)
public static double round1(double value, int scale) {
return Math.round(value * Math.pow(10, scale)) / Math.pow(10, scale);
}
2)
public static float round2(float number, int scale) {
int pow = 10;
for (int i = 1; i < scale; i++)
pow *= 10;
float tmp = number * pow;
return ( (float) ( (int) ((tmp - (int) tmp) >= 0.5f ? tmp + 1 : tmp) ) ) / pow;
}
3)
public static float round3(float d, int decimalPlace) {
return BigDecimal.valueOf(d).setScale(decimalPlace, BigDecimal.ROUND_HALF_UP).floatValue();
}
Number is 0.23453f
We'll test 100,000 iterations each method.
Results:
Time 1 - 18 ms
Time 2 - 1 ms
Time 3 - 378 ms
Tested on laptop
Intel i3-3310M CPU 2.4GHz
How to round float to 2 decimal places in Java?
Truncate to 2 decimal places in Java
How to round a number to n decimal places in Java - Stack Overflow
how to limit or round a float to only two decimals without rounding up
Videos
Well this one works...
double roundOff = Math.round(a * 100.0) / 100.0;
Output is
123.14
Or as @Rufein said
double roundOff = (double) Math.round(a * 100) / 100;
this will do it for you as well.
double d = 2.34568;
DecimalFormat f = new DecimalFormat("##.00");
System.out.println(f.format(d));
Just did an OA about it and it's driving me crazy. e.g. 1, 2, 3 -> 1.00, 2.00, 3.00
The result needs to be a float, not String.
I tried BigDecimal, DecimalFormat and then use Float.valueOf(<formatted string>), and I can only have 1.0, 2.0, 3.0... for float types that are actually integers. Is it possible in Java?
Sry I don't have a StackOverflow acc so I just post it here, I guess it's kinda related to 'CSMajors'.
Hi, how do i truncate the result of a calculation to 2 decimals; for instance if the result is 19.899 or 19.892 i want the system to print 19.89 regardless. Thanks and merry christmas:))
Keep in mind that String.format() and DecimalFormat produce string using default Locale. So they may write formatted number with dot or comma as a separator between integer and decimal parts. To make sure that rounded String is in the format you want use java.text.NumberFormat as so:
Locale locale = Locale.ENGLISH;
NumberFormat nf = NumberFormat.getNumberInstance(locale);
// for trailing zeros:
nf.setMinimumFractionDigits(2);
// round to 2 digits:
nf.setMaximumFractionDigits(2);
System.out.println(nf.format(.99));
System.out.println(nf.format(123.567));
System.out.println(nf.format(123.0));
Will print in English locale (no matter what your locale is): 0.99 123.57 123.00
The example is taken from Farenda - how to convert double to String correctly.
the following method could be used if need double
double getRandom(int decimalPoints) {
double a = Math.random();
int multiplier = (int) Math.pow(10, decimalPoints);
int b = (int) (a * multiplier);
return b / (double) multiplier;
}
for example getRandom(2)