With PIL it should work like this
from PIL import Image
I8 = (((I - I.min()) / (I.max() - I.min())) * 255.9).astype(np.uint8)
img = Image.fromarray(I8)
img.save("file.png")
Answer from eickenberg on Stack OverflowWith PIL it should work like this
from PIL import Image
I8 = (((I - I.min()) / (I.max() - I.min())) * 255.9).astype(np.uint8)
img = Image.fromarray(I8)
img.save("file.png")
There is also a possibility to use scikit-image, then there is no need to convert numpy array into a PIL object.
from skimage import io
io.imsave('output.tiff', I.astype(np.uint16))
python - How to save 2D float numpy arrays losslessly into a grayscale image while preserving resolution? - Stack Overflow
python - Saving a Numpy array as an image - Stack Overflow
python - Converting 2D Numpy array of grayscale values to a PIL image - Stack Overflow
python - Saving a Numpy array as an image (instructions) - Stack Overflow
Using PIL, save a NumPy array arr by doing:
from PIL import Image
im = Image.fromarray(arr)
im.save("your_file.jpeg")
See the docs for available data formats, including JPEG, PNG, and so on.
This uses PIL, but maybe some might find it useful:
import scipy.misc
scipy.misc.imsave('outfile.jpg', image_array)
EDIT: The current scipy version started to normalize all images so that min(data) become black and max(data) become white. This is unwanted if the data should be exact grey levels or exact RGB channels. The solution:
import scipy.misc
scipy.misc.toimage(image_array, cmin=0.0, cmax=...).save('outfile.jpg')
I think the answer is wrong. The Image.fromarray( ____ , 'L') function seems to only work properly with an array of integers between 0 and 255. I use the np.uint8 function for this.
You can see this demonstrated if you try to make a gradient.
import numpy as np
from PIL import Image
# gradient between 0 and 1 for 256*256
array = np.linspace(0,1,256*256)
# reshape to 2d
mat = np.reshape(array,(256,256))
# Creates PIL image
img = Image.fromarray(np.uint8(mat * 255) , 'L')
img.show()
Makes a clean gradient
vs
import numpy as np
from PIL import Image
# gradient between 0 and 1 for 256*256
array = np.linspace(0,1,256*256)
# reshape to 2d
mat = np.reshape(array,(256,256))
# Creates PIL image
img = Image.fromarray( mat , 'L')
img.show()
Has the same kind of artifacting.
If I understood you question, you want to get a grayscale image using PIL.
If this is the case, you do not need to multiply each pixels by 255.
The following worked for me
import numpy as np
from PIL import Image
# Creates a random image 100*100 pixels
mat = np.random.random((100,100))
# Creates PIL image
img = Image.fromarray(mat, 'L')
img.show()
You might be better off using PIL:
from PIL import Image
import numpy as np
data = np.random.random((100,100))
#Rescale to 0-255 and convert to uint8
rescaled = (255.0 / data.max() * (data - data.min())).astype(np.uint8)
im = Image.fromarray(rescaled)
im.save('test.png')
import matplotlib.pyplot as plt
import numpy as np
plt.imshow(np.random.random(100, 100))
plt.savefig('')
As the assertion states, adaptiveThreshold() requires a single-channeled 8-bit image.
Assuming your floating-point image ranges from 0 to 1, which appears to be the case, you can convert the image by multiplying by 255 and casting to np.uint8:
float_img = np.random.random((4,4))
im = np.array(float_img * 255, dtype = np.uint8)
threshed = cv2.adaptiveThreshold(im, 255, cv2.ADAPTIVE_THRESH_MEAN_C, cv2.THRESH_BINARY, 3, 0)
This one worked for me:
uint_img = np.array(float_arr*255).astype('uint8')
grayImage = cv2.cvtColor(uint_img, cv2.COLOR_GRAY2BGR)