Unless Splitter is doing any magic, the getTokenizeString method is obsolete here. You can perform the entire processing as a single operation:
Map<String,String> map = Pattern.compile("\\s*-\\s*")
.splitAsStream(responseString.trim())
.map(s -> s.split("~", 2))
.collect(Collectors.toMap(a -> a[0], a -> a.length>1? a[1]: ""));
By using the regular expression \s*-\s* as separator, you are considering white-space as part of the separator, hence implicitly trimming the entries. There’s only one initial trim operation before processing the entries, to ensure that there is no white-space before the first or after the last entry.
Then, simply split the entries in a map step before collecting into a Map.
Unless Splitter is doing any magic, the getTokenizeString method is obsolete here. You can perform the entire processing as a single operation:
Map<String,String> map = Pattern.compile("\\s*-\\s*")
.splitAsStream(responseString.trim())
.map(s -> s.split("~", 2))
.collect(Collectors.toMap(a -> a[0], a -> a.length>1? a[1]: ""));
By using the regular expression \s*-\s* as separator, you are considering white-space as part of the separator, hence implicitly trimming the entries. There’s only one initial trim operation before processing the entries, to ensure that there is no white-space before the first or after the last entry.
Then, simply split the entries in a map step before collecting into a Map.
First of all, you don't have to split the same String twice.
Second of all, check the length of the array to determine if a value is present for a given key.
HashMap<String, String> map=
list.stream()
.map(s -> s.split("~"))
.collect(Collectors.toMap(a -> a[0], a -> a.length > 1 ? a[1] : ""));
This is assuming you want to put the key with a null value if a key has no corresponding value.
Or you can skip the list variable :
HashMap<String, String> map1 =
MyClass.getTokenizeString(responseString, "-")
.stream()
.map(s -> s.split("~"))
.collect(Collectors.toMap(a -> a[0], a -> a.length > 1 ? a[1] : ""));
You can use the following snippet for this:
Map<String, Map<String, String>> result = Arrays.stream(samp.split(","))
.map(i -> i.split("-"))
.collect(Collectors.groupingBy(a -> a[0], Collectors.toMap(a -> a[1], a -> a[2])));
First it creates a Stream of your items, which are mapped to a stream of arrays, containing the subitems. At the end you collect all by using group by on the first subitem and create an inner map with the second value as key and the last one as value.
The result is:
{101={1=5, 2=4}, 102={1=5, 2=5, 3=5}, 103={1=4}}
Map<String, Map<String, String>> map = Arrays.stream(samp.split(","))
.map(s -> s.split("-"))
.collect(Collectors.toMap(
o -> o[0],
o -> Map.of(o[1], o[2]),
(m1, m2) -> Stream.concat(m1.entrySet().stream(), m2.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))));
Map.of is from Java 9, you can use AbstractMap.SimpleEntry if you are on Java 8.
Samuel's answer is better though, much concise.
You could use a loop to iterate over the key value pairs and put them into the map:
String[] cookieArr = cookies.split(";");
for(String cookieString : cookieArr){
String[] pair = cookieString.split("=");
if(pair.length < 2){
continue;
}
map.put(pair[0], pair[1]);
}
The if is only there to prevent ArrayIndexOutOfBounds expcetions if cookie string is malformed
an alternativ would be using a stream:
Arrays.stream(cookies.split(";")).forEach(cookieStr -> map.put(cookieStr.split("=")[0], cookieStr.split("=")[1]));
As mentioned by @WJS in the comment, you could use map.putIfAbsent(key, vlaue) instead of map.put(key, value) to prevent overriding of values. But in case of cookies it could be a desired behavior to overwrite the old value with the new.
You could do it like this. It presumes your format is consistent.
- first splits each k/v pair on ";"
- the splits on "=" into key and value.
- and adds to map.
- if duplicate keys show up, the first one encountered takes precedence (if you want the latest value for a duplicate key then use
(a, b)-> bas the merge lambda.)
String cookies = "i=lol;haha=noice;df3=ddtb";
Map<String, String> map = Arrays.stream(cookies.split(";"))
.map(str -> str.split("=")).collect(Collectors
.toMap(a -> a[0], a->a[1], (a, b) -> a));
map.entrySet().forEach(System.out::println);
Prints
df3=ddtb
haha=noice
i=lol
There is no need to reinvent the wheel. The Google Guava library provides the Splitter class.
Here's how you can use it along with some test code:
package com.sandbox;
import com.google.common.base.Splitter;
import org.junit.Test;
import java.util.Map;
import static org.junit.Assert.assertEquals;
public class SandboxTest {
@Test
public void testQuestionInput() {
Map<String, String> map = splitToMap("A=4 H=X PO=87");
assertEquals("4", map.get("A"));
assertEquals("X", map.get("H"));
assertEquals("87", map.get("PO"));
}
private Map<String, String> splitToMap(String in) {
return Splitter.on(" ").withKeyValueSeparator("=").split(in);
}
}
Java 8 to the rescue!
import static java.util.stream.Collectors.*;
Map<String, String> result = Arrays.stream(input.split(" "))
.map(s -> s.split("="))
.collect(Collectors.toMap(
a -> a[0], //key
a -> a[1] //value
));
NOTE: Assuming no duplicates. Otherwise look into the 3rd 'mergeFunction' argument.
I would use split
String text = "A=B&C=D&E=F";
Map<String, String> map = new LinkedHashMap<String, String>();
for(String keyValue : text.split(" *& *")) {
String[] pairs = keyValue.split(" *= *", 2);
map.put(pairs[0], pairs.length == 1 ? "" : pairs[1]);
}
EDIT allows for padded spaces and a value with an = or no value. e.g.
A = minus- & C=equals= & E==F
just use guava Splitter
String src="A=B&C=D&E=F";
Map map= Splitter.on('&').withKeyValueSeparator('=').split(src);
Split the string by , to get individual map entries. Then split them by = to get the key and the value.
Map<String, String> reconstructedUtilMap = Arrays.stream(utilMapString.split(","))
.map(s -> s.split("="))
.collect(Collectors.toMap(s -> s[0], s -> s[1]));
Note: As pointed out by Andreas@ in the comments, this is not a reliable way to convert between a map and a string
EDIT: Thanks to Holger for this suggestion.
Use s.split("=", 2) to ensure that the array is never larger than two elements. This will be useful to not lose the contents (when the value has =)
Example: when the input string is "a=1,b=2,c=3=44=5555"
you will get {a=1, b=2, c=3=44=5555}
Earlier (just using s.split("=")) will give
{a=1, b=2, c=3}
Here is another option which streams a list of 1=1 etc. terms into a map.
String input = "1=1,2=2,3=3,4=4,5=5";
Map<String, String> map = Arrays.asList(input.split(",")).stream().collect(
Collectors.toMap(x -> x.replaceAll("=\\d+$", ""),
x -> x.replaceAll("^\\d+=", "")));
System.out.println(Collections.singletonList(map));
[{1=1, 2=2, 3=3, 4=4, 5=5}]
You can simply use split() and do something like this:
public static void main (String[] args) throws Exception {
String input = "{A=1,B=2,C=3}";
Map<String, Integer> map = new HashMap<>();
for(String str : input.substring(1,input.length() - 1).split(",")) {
String[] data = str.split("=");
map.put(data[0],Integer.parseInt(data[1]));
}
System.out.println(map);
}
Output:
{A=1, B=2, C=3}
Here's a one liner:
Map<String, Integer> map =
Arrays.stream(str.replaceAll("^.|.$", "").split(","))
.map(s -> s.split("="))
.collect(Collectors.toMap(a -> a[0], a -> new Integer(a[1])));
Disclaimer: Code may not compile or work as it was thumbed in on my phone (but there's a reasonable chance it will work)
This first trims the first and last chars, then splits on comma, then splits again on equals sign, then collects to a map. Voila.
Parse the JSONObject and create HashMap
public static void jsonToMap(String t) throws JSONException {
HashMap<String, String> map = new HashMap<String, String>();
JSONObject jObject = new JSONObject(t);
Iterator<?> keys = jObject.keys();
while( keys.hasNext() ){
String key = (String)keys.next();
String value = jObject.getString(key);
map.put(key, value);
}
System.out.println("json : "+jObject);
System.out.println("map : "+map);
}
Tested output:
json : {"phonetype":"N95","cat":"WP"}
map : {cat=WP, phonetype=N95}
You can use Google's Gson library to convert json to Hashmap. Try below code
String jsonString = "Your JSON string";
HashMap<String,String> map = new Gson().fromJson(jsonString, new TypeToken<HashMap<String, String>>(){}.getType());