I recommend using python-dateutil. Its parser has been able to parse every date format I've thrown at it so far.
>>> from dateutil import parser
>>> parser.parse("Tue Jun 22 07:46:22 EST 2010")
datetime.datetime(2010, 6, 22, 7, 46, 22, tzinfo=tzlocal())
>>> parser.parse("Fri, 11 Nov 2011 03:18:09 -0400")
datetime.datetime(2011, 11, 11, 3, 18, 9, tzinfo=tzoffset(None, -14400))
>>> parser.parse("Sun")
datetime.datetime(2011, 12, 18, 0, 0)
>>> parser.parse("10-11-08")
datetime.datetime(2008, 10, 11, 0, 0)
and so on. No dealing with strptime() format nonsense... just throw a date at it and it Does The Right Thing.
I recommend using python-dateutil. Its parser has been able to parse every date format I've thrown at it so far.
>>> from dateutil import parser
>>> parser.parse("Tue Jun 22 07:46:22 EST 2010")
datetime.datetime(2010, 6, 22, 7, 46, 22, tzinfo=tzlocal())
>>> parser.parse("Fri, 11 Nov 2011 03:18:09 -0400")
datetime.datetime(2011, 11, 11, 3, 18, 9, tzinfo=tzoffset(None, -14400))
>>> parser.parse("Sun")
datetime.datetime(2011, 12, 18, 0, 0)
>>> parser.parse("10-11-08")
datetime.datetime(2008, 10, 11, 0, 0)
and so on. No dealing with strptime() format nonsense... just throw a date at it and it Does The Right Thing.
Since strptime returns a datetime object which has tzinfo attribute, We can simply replace it with desired timezone.
>>> import datetime
>>> date_time_str = '2018-06-29 08:15:27.243860'
>>> date_time_obj = datetime.datetime.strptime(date_time_str, '%Y-%m-%d %H:%M:%S.%f').replace(tzinfo=datetime.timezone.utc)
>>> date_time_obj.tzname()
'UTC'
`Time::Piece` and `strptime()` processing timezones documentation discrepancy
%Z in strptime doesn't match EST and others
How to use strptime() parsing a datetime string with a timezone offset?
Is it possible to use the strptime() to handle the UTC or named time zones (e.g., EST, PST)?
How to use the strptime() function in Python?
My log files have the date/time formatted as: 2022-01-01T11:53:42-08:00. I need to convert that to a Unixtime. I think strptime() is the easiest way to do this?
Here is the code I came up with to process this specific time string.
#!/usr/bin/env perl use strict; use warnings; use Time::Piece; my $input = '2022-01-01T11:53:42-08:00'; my $tp = Time::Piece->strptime($input, "%Y-%m-%dT%H:%M:%S"); print "Input : $input\n"; print "Epoch : " . $tp->epoch . "\n"; print "Format: " . $tp->cdate . "\n";
When I run this I get an error about the timezone string at the end
Garbage at end of string in strptime: -08:00 at /usr/lib64/perl5/Time/Piece.pm line 598. Perhaps a format flag did not match the actual input? at /usr/lib64/perl5/Time/Piece.pm line 598.
The documentation says to add %z to process timezones, but when I do that it fails completely. How do I make strptime() process this string correctly? Is there a better/easier way to convert this?
strptime() is implemented in pure Python. Unlike strftime(); it [which directives are supported] doesn't depend on platform. %z is supported since Python 3.2:
>>> from datetime import datetime
>>> datetime.strptime('24/Aug/2014:17:57:26 +0200', '%d/%b/%Y:%H:%M:%S %z')
datetime.datetime(2014, 8, 24, 17, 57, 26, tzinfo=datetime.timezone(datetime.timedelta(0, 7200)))
how to parse Email time zone indicator using strptime() without being aware of locale time?
There is no concrete timezone implementation in Python 2.7. You could easily implement the UTC offset parsing, see How to parse dates with -0400 timezone string in python?
In continue to @j-f-sebastians 's answer, here is a fix for python 2.7
Instead of using:
datetime.strptime(t,'%Y-%m-%dT%H:%M %z')
use the timedelta to account for the timezone, like this:
from datetime import datetime,timedelta
def dt_parse(t):
ret = datetime.strptime(t[0:16],'%Y-%m-%dT%H:%M')
if t[17]=='+':
ret-=timedelta(hours=int(t[18:20]),minutes=int(t[20:]))
elif t[17]=='-':
ret+=timedelta(hours=int(t[18:20]),minutes=int(t[20:]))
return ret
print(dt_parse('2017-01-12T14:12 -0530'))