This works for me:
var test = [1, 2, 3]
var n = 2
var test2 = test[0..<n]
Your issue could be with how you're declaring your array to begin with.
EDIT:
To fix your function, you have to cast your Slice to an array:
func aFunction(numbers: Array<Int>, position: Int) -> Array<Int> {
var newNumbers = Array(numbers[0..<position])
return newNumbers
}
// test
aFunction([1, 2, 3], 2) // returns [1, 2]
Answer from Cezary Wojcik on Stack OverflowThis works for me:
var test = [1, 2, 3]
var n = 2
var test2 = test[0..<n]
Your issue could be with how you're declaring your array to begin with.
EDIT:
To fix your function, you have to cast your Slice to an array:
func aFunction(numbers: Array<Int>, position: Int) -> Array<Int> {
var newNumbers = Array(numbers[0..<position])
return newNumbers
}
// test
aFunction([1, 2, 3], 2) // returns [1, 2]
#1. Using Array subscript with range
With Swift 5, when you write…
let newNumbers = numbers[0...position]
… newNumbers is not of type Array<Int> but is of type ArraySlice<Int>. That's because Array's subscript(_:) returns an ArraySlice<Element> that, according to Apple, presents a view onto the storage of some larger array.
Besides, Swift also provides Array an initializer called init(_:) that allows us to create a new array from a sequence (including ArraySlice).
Therefore, you can use subscript(_:) with init(_:) in order to get a new array from the first n elements of an array:
let array = Array(10...14) // [10, 11, 12, 13, 14]
let arraySlice = array[0..<3] // using Range
//let arraySlice = array[0...2] // using ClosedRange also works
//let arraySlice = array[..<3] // using PartialRangeUpTo also works
//let arraySlice = array[...2] // using PartialRangeThrough also works
let newArray = Array(arraySlice)
print(newArray) // prints [10, 11, 12]
#2. Using Array's prefix(_:) method
Swift provides a prefix(_:) method for types that conform to Collection protocol (including Array). prefix(_:) has the following declaration:
func prefix(_ maxLength: Int) -> ArraySlice<Element>
Returns a subsequence, up to maxLength in length, containing the initial elements.
Apple also states:
If the maximum length exceeds the number of elements in the collection, the result contains all the elements in the collection.
Therefore, as an alternative to the previous example, you can use the following code in order to create a new array from the first elements of another array:
let array = Array(10...14) // [10, 11, 12, 13, 14]
let arraySlice = array.prefix(3)
let newArray = Array(arraySlice)
print(newArray) // prints [10, 11, 12]
With Swift 4, there is many ways to solve your problem. According to your needs, you may choose one of the six following patterns.
#1. Using Array dropFirst() method
let array = ["a", "b", "c"]
let arraySlice = array.dropFirst()
let newArray = Array(arraySlice)
print(newArray) // prints ["b", "c"]
#2. Using Array suffix(from:) method
let array = ["a", "b", "c"]
let arraySlice = array.suffix(from: 1)
let newArray = Array(arraySlice)
print(newArray) // prints ["b", "c"]
#3. Using Array suffix(_:) method
let array = ["a", "b", "c"]
let arraySlice = array.suffix(array.endIndex.advanced(by: -1))
// let arraySlice = array.suffix(array.count - 1) // also works
let newArray = Array(arraySlice)
print(newArray) // prints ["b", "c"]
#4. Using Array subscript(_:) and CountableRange
let array = ["a", "b", "c"]
let range = array.startIndex.advanced(by: 1) ..< array.endIndex
// let range = 1 ..< array.count // also works
let arraySlice = array[range]
let newArray = Array(arraySlice)
print(newArray) // prints ["b", "c"]
#5. Using Array subscript(_:) and CountableClosedRange
let array = ["a", "b", "c"]
let range = 1 ... array.count - 1 // also works
let arraySlice = array[range]
let newArray = Array(arraySlice)
print(newArray) // prints ["b", "c"]
#6. Using Array subscript(_:) and CountablePartialRangeFrom
let array = ["a", "b", "c"]
let range = 1...
let arraySlice = array[range]
let newArray = Array(arraySlice)
print(newArray) // prints ["b", "c"]
You can get sub range of an swift array like that:
let array =[ "a", "b", "c"]
//be sure that your array.count has more than 1 item (in this case)
let subArray1 = array[1..<array.count]
print(subArray1)
//or
let subArray2 = array[1...array.count-1]
print(subArray2)
This is 2 notes from Swift Programming Language book
“Use .. to make a range that omits its upper value, and use ... to make a range that includes both values.”
And
“If you try to use subscript syntax to retrieve or set a value for an index that is outside of an array’s existing bounds, you will trigger a runtime error. However, you can check that an index is valid before using it, by comparing it to the array’s count property. Except when count is 0 (meaning the array is empty), the largest valid index in an array will always be count - 1, because arrays are indexed from zero.”