Yes you are right. You have degrees of freedom for the distribution. Here we have a 2-sided test, so we should be looking at a right (or left) tailed area of with degrees of freedom. Using the table below, we can extract the critical value for the desired confidence interval. (At the rows, you should be looking at and at the columns you should be reading ).

Answer from Ahmad Bazzi on Stack Exchange
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University of Regina
uregina.ca › ~gingrich › tt.pdf pdf
t-distribution Confidence Level 60% 70% 80% 85% 90% 95% 98% 99% 99.8% 99.9%
Confidence Level · 60% 70% 80% 85% 90% 95% 98% 99% 99.8% 99.9% Level of Significance · 2 Tailed · 0.40 · 0.30 · 0.20 · 0.15 · 0.10 · 0.05 · 0.02 · 0.01 · 0.002 · 0.001 · 1 Tailed · 0.20 · 0.15 · 0.10 · 0.075 · 0.05 · 0.025 · 0.01 · 0.005 ·
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Coconino Community College
coconino.edu › resources › files › pdfs › academics › sabbatical-reports › kate-kozak › appendix_table.pdf pdf
Appendix: Critical Values Tables 433 Appendix: Critical Value Tables
Table A.2: Critical Values for t-Interval · Appendix: Critical Values Tables · 434 · Table A.1: Normal Critical Values for Confidence Levels · Confidence Level, C · Critical Value, zc · 99% 2.575 · 98% 2.33 · 95% 1.96 · 90% 1.645 · 80% 1.28 · Critical Values for Zc created using ...
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Richland College
people.richland.edu › james › lecture › m170 › tbl-t.html
Student's T Critical Values
The values in the table are the areas critical values for the given areas in the right tail or in both tails
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Colorado State University
stat.colostate.edu › inmem › gumina › st201 › pdf › Utts-Heckard_t-Table.pdf pdf
0 t critical value -t critical value t curve Central area t critical values
Confidence area captured: 0.90 · 0.95 · 0.98 · 0.99 · Confidence level: 90% 95% 98% 99% 1 · 6.31 · 12.71 · 31.82 · 63.66 · 2 · 2.92 · 4.30 · 6.97 · 9.93 · 3 · 2.35 · 3.18 · 4.54 · 5.84 · 4 · 2.13 · 2.78 · 3.75 · 4.60 · 5 · 2.02 · 2.57 ·
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Dummies
dummies.com › article › academics-the-arts › math › statistics › how-to-find-t-values-for-confidence-intervals-169841
How to Find t-Values for Confidence Intervals | dummies
July 2, 2025 - You need to take that into account. For example, a t-value for a 90% confidence interval has 5% for its greater-than probability and 5% for its less-than probability (taking 100% minus 90% and dividing by 2).
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Cuny
mccarthymat150.commons.gc.cuny.edu › units-10 › 15-confidence-intervals-and-t-distribution
15. Confidence Intervals and the t-distribution | Professor McCarthy Statistics
Answer to Question 9. The row is the degrees of freedom (d.f.). For confidence intervals for $\mu_x$ the df = $n-1$. So, the d.f. $= n-1 = 64 – 1 = 63$. We want the 98% confidence interval, so we look in column that says 98% confidence level. The intersection of the row for 63 d.f.
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Confidence intereval for population mean. A 98% confidence interval for $\mu$ is of the form $\bar X \pm t^* s/\sqrt{n},$ where $t^*$ cuts off 1% from the upper tail of Student's t distribution with $df = n-1.$ So you are almost correct for that part. Here $t^* = 2.365.$ I get the CI $(39.00, 49.44)$ from the following brief R session.

 a = 44.22;  s = 22.0773;  n = 100
 t.c = qt(.99, n-1);  pm = c(-1,1)
 a + pm*t.c*s/sqrt(n)
 ## 38.99959 49.44041

Confidence interval for population variance. To get a 98% CI for $\sigma^2,$ one can use the fact that $(n-1)s^2/\sigma^2 \sim Chisq(df = n - 1).$ So if $L$ and $U$ cut 1% from the lower and upper tails of $Chisq(99),$ we have $$P\left(L \le \frac{(n-1)s^2}{\sigma^2} \le U \right) = .98$$ from which we get $$\left((n-1)s^2/U,\; (n-1)s^2/L\right)$$ as a 98% CI for $\sigma^2.$ In particular, for your data the CI is $(358.4, 697.0).$ (You could get $L$ and $U$ from a suitable printed table of the chi-squared distribution.) Notice that $s^2 = 487.4$ is contained in this interval, but is $not$ at the very center of the interval---because the chi-squared distribution is not symmetrical. Take the square root of both endpoints if you want a CI for $\sigma.$

 (n-1)*s^2/qchisq(c(.99,.01),n-1)
 ## 358.3833 697.0011

Note: The so-called 'rule of 30' may be roughly OK for 95% CIs because when $n \ge 30$ we have $df \ge 29$ and the values that cut of .025 from the upper tail of the t distribution are 'near' 2.0, just as 1.96 is 'near' 2.0:

 qt(.975, 29:35)  # df from 29 through 35
 ## 2.045230 2.042272 2.039513 2.036933 2.034515 2.032245 2.030108

However, this sort of approximation does not generally work well for CIs at levels other than 95%. None of the values below is really 'near' 2.326:

 qt(.99, 29:35)
 ## 2.462021 2.457262 2.452824 2.448678 2.444794 2.441150 2.437723

Please check your t table, if R code mystifies you.

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Penn State Statistics
online.stat.psu.edu › stat200 › book › export › html › 166
8.2.2 - Confidence Intervals
Because \(t\) values vary depending on the number of degrees of freedom (df), you will need to use statistical software to look up the appropriate \(t\) value for each confidence interval that you construct. The degrees of freedom will be based on the sample size. Since we are working with one sample here, \(df=n-1\). To find the t* multiplier for a 98% confidence interval with 15 degrees of freedom:
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Yale Statistics
stat.yale.edu › Courses › 1997-98 › 101 › confint.htm
Confidence Intervals
Descriptive Statistics Variable ... TEMP 96.300 100.800 97.800 98.700 To find a 95% confidence interval for the mean based on the sample mean 98.249 and sample standard deviation 0.733, first find the 0.025 critical value t* for 129 degrees of freedom....
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Study.com
study.com › skill › learn › finding-the-critical-t-value-for-a-given-confidence-level-sample-size-explanation.html
Finding the Critical T-value for a Given Confidence Level & Sample Size | Statistics and Probability | Study.com
A company wants to estimate the mean price of all used cars in its state. Based on a random sample of 1000 used cars, the mean price was 24,500 dollars with a sample standard deviation of 8500 dollars. The company wants to construct a 99% confidence interval for the population mean used car price.
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Calculator.net
calculator.net › home › math › confidence interval calculator
Confidence Interval Calculator
Calculator to compute the confidence interval or margin of error of a sample based on the desired confidence level. It also provides an error bar diagram.
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Studocu
studocu.com › pensacola state college › elementary statistics › question
[Solved] Find the critical value t 2 needed to construct a 98 confidence - Elementary Statistics (STA 2023) - Studocu
July 27, 2023 - Now, we look up the t-value in the t-distribution table that corresponds to df = 11 and α/2 = 0.01. If you don't have a t-distribution table, you can use a statistical calculator or an online tool to find the t-value.
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Brainly
brainly.com › mathematics › high school
To construct a 98% confidence interval, we need the t value with degree of freedom 49 corresponding to an - brainly.com
The upper tail area corresponding to this value is 1% + 0.99% + 0.01% + 0.02% = 2.02% since the t-distribution is symmetric. Therefore, to construct a 98% confidence interval, we need to multiply the standard error by 2.68 and add and subtract ...
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Wyzant
wyzant.com › resources › ask an expert
For a confidence level of 98% with a sample size of 18, find the critical t value. | Wyzant Ask An Expert
December 8, 2023 - Look up a t-table online. The first one you see will be from San Jose State--this is a nice, comprehensive one. Sorry I cannot link here as Wyzant reviews posts when I link. Your test is two-sided, confidence levels are at the bottom of the table, so look for 98% there.
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Socscistatistics
socscistatistics.com › confidenceinterval › default2.aspx
Confidence Interval Calculator: Single-Sample T Statistic
This simple confidence interval calculator uses a t statistic and sample mean (M) to generate an interval estimate of a population mean (μ).