This is a well-known problem with Java type erasure: T is just a type variable, and you must indicate actual class, usually as Class argument. Without such information, best that can be done is to use bounds; and plain T is roughly same as 'T extends Object'. And Jackson will then bind JSON Objects as Maps.
In this case, tester method needs to have access to Class, and you can construct
JavaType type = mapper.getTypeFactory().
constructCollectionType(List.class, Foo.class)
and then
List<Foo> list = mapper.readValue(new File("input.json"), type);
Answer from StaxMan on Stack OverflowThis is a well-known problem with Java type erasure: T is just a type variable, and you must indicate actual class, usually as Class argument. Without such information, best that can be done is to use bounds; and plain T is roughly same as 'T extends Object'. And Jackson will then bind JSON Objects as Maps.
In this case, tester method needs to have access to Class, and you can construct
JavaType type = mapper.getTypeFactory().
constructCollectionType(List.class, Foo.class)
and then
List<Foo> list = mapper.readValue(new File("input.json"), type);
'JavaType' works !!
I was trying to unmarshall (deserialize) a List in json String to ArrayList java Objects and was struggling to find a solution since days.
Below is the code that finally gave me solution.
Code:
JsonMarshallerUnmarshaller<T> {
T targetClass;
public ArrayList<T> unmarshal(String jsonString) {
ObjectMapper mapper = new ObjectMapper();
AnnotationIntrospector introspector = new JacksonAnnotationIntrospector();
mapper.getDeserializationConfig()
.withAnnotationIntrospector(introspector);
mapper.getSerializationConfig()
.withAnnotationIntrospector(introspector);
JavaType type = mapper.getTypeFactory().
constructCollectionType(
ArrayList.class,
targetclass.getClass());
try {
Class c1 = this.targetclass.getClass();
Class c2 = this.targetclass1.getClass();
ArrayList<T> temp = (ArrayList<T>)
mapper.readValue(jsonString, type);
return temp ;
} catch (JsonParseException e) {
e.printStackTrace();
} catch (JsonMappingException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null ;
}
}
TypeReference requires you to specify parameters statically, not dynamically, so it does not work if you need to further parameterize types.
What I think you need is JavaType: you can build instances dynamically by using TypeFactory. You get an instance of TypeFactory via ObjectMapper.getTypeFactory(). You can also construct JavaType instances from simple Class as well as TypeReference.
One approach will be to define a Jackson JavaType representing a list of items of type clazz. You still need to have access to the class of the generic parameter at runtime. The usual approach is something like
<T> class XX { XX(Class<T> clazz, ...) ... }
to pass the class of the generic parameter into the generic class at construction.
Upon access to the Class clazz variable you can construct a Jackson JavaType representing, for example, a list of items of class clazz with the following statement.
JavaType itemType = mapper.getTypeFactory().constructCollectionType(List.class, clazz);
I hope it helped. I am using this approach in my own code.