Yes. As of TypeScript 3.7 (released on November 5, 2019), this feature is supported and is called Optional Chaining:
At its core, optional chaining lets us write code where TypeScript can immediately stop running some expressions if we run into a
nullorundefined. The star of the show in optional chaining is the new?.operator for optional property accesses.
Refer to the TypeScript 3.7 release notes for more details.
Prior to version 3.7, this was not supported in TypeScript, although it was requested as early as Issue #16 on the TypeScript repo (dating back to 2014).
As far as what to call this operator, there doesn't appear to be a consensus. In addition to "optional chaining" (which is also what it's called in JavaScript and Swift), there are a couple of other examples:
- CoffeeScript refers to it as the existential operator (specifically, the "accessor variant" of the existential operator):
The accessor variant of the existential operator
?.can be used to soak up null references in a chain of properties. Use it instead of the dot accessor.in cases where the base value may be null or undefined.
- C# calls this a null-conditional operator.
a null-conditional operator applies a member access,
?., or element access,?[], operation to its operand only if that operand evaluates to non-null; otherwise, it returnsnull.
- Kotlin refers to it as the safe call operator.
There are probably lots of other examples, too.
Answer from Donut on Stack OverflowYes. As of TypeScript 3.7 (released on November 5, 2019), this feature is supported and is called Optional Chaining:
At its core, optional chaining lets us write code where TypeScript can immediately stop running some expressions if we run into a
nullorundefined. The star of the show in optional chaining is the new?.operator for optional property accesses.
Refer to the TypeScript 3.7 release notes for more details.
Prior to version 3.7, this was not supported in TypeScript, although it was requested as early as Issue #16 on the TypeScript repo (dating back to 2014).
As far as what to call this operator, there doesn't appear to be a consensus. In addition to "optional chaining" (which is also what it's called in JavaScript and Swift), there are a couple of other examples:
- CoffeeScript refers to it as the existential operator (specifically, the "accessor variant" of the existential operator):
The accessor variant of the existential operator
?.can be used to soak up null references in a chain of properties. Use it instead of the dot accessor.in cases where the base value may be null or undefined.
- C# calls this a null-conditional operator.
a null-conditional operator applies a member access,
?., or element access,?[], operation to its operand only if that operand evaluates to non-null; otherwise, it returnsnull.
- Kotlin refers to it as the safe call operator.
There are probably lots of other examples, too.
It is now possible, see answer of user "Donut".
Old answer: Standard JavaScript behaviour regarding boolean operators has something that may help. The boolean methods do not return true or false when comparing objects, but in case of OR the first value that is equal to true.
Not as nice as a single ?, but it works:
var thing = foo && foo.bar || null;
You can use as many && as you like:
var thing = foo && foo.bar && foo.bar.check && foo.bar.check.x || null;
Default values are also possible:
var name = person && person.name || "Unknown user";
Videos
Take this interface for example
interface Item {
value?: number
}Which among the two do you prefer if you will be accessing the value property of an item and why?
console.log(item.value ?? 1.00) // 1.00 is the fallback value
console.log(item.value || 1.00) // 1.00 is the fallback value
Personally, I prefer to use the nullish coalescing operator ?? for fallback values since it's more explicit and it sames me from the weird falsy values that JavaScript has.
Yes, as of Typescript 3.7 you can now do this via optional-chaining
person?.getName()?.firstName
gets transpiled to
let firstName = person === null || person === void 0 ? void 0 : (_person$getName = person.getName()) === null || _person$getName === void 0 ? void 0 : _person$getName.firstName;
Note the check for null. This will work as expected if for example person is defined as
let person:any = null; //no runtime TypeError when calling person?.getName()
However if person is defined as
let person:any = {};//Uncaught TypeError: person.getName is not a function
See also this similar stackoverflow question
No, as of now safe navigation operatior is still not implemented in Typescript: https://github.com/Microsoft/TypeScript/issues/16
However according to the latest standardization meeting notes it has been proposed, so maybe v3 :)
https://github.com/tc39/agendas/blob/master/2017/07.md