Does Steam not have an Update All button or am I missing something?
Is it possible to update all my apps in one go, just like my Android phone?
ruby on rails - update_all with a method - Stack Overflow
How to switch back from this awful "new Reddit" update?
Videos
Hey there,
Everytime I open the odd app (WinSCP, MobaXTerm etc) I always get prompted that newer updates are available.
I'd prefer it if these software updates just updated all together, irrespective if I opened the apps or not, just like my Android phone.
Is this possible in Windows?
If the compute_sum function can't be translated into sql, then you cannot do update_all on all records at once. You will need to iterate over the individual instances. However, you could speed it up if there are a lot of repeated sets of values in the columns, by only doing the calculation once per set of inputs, and then doing one mass-update per calculation. eg
Result.all.group_by{|result| [result.x, result.y]}.each do |inputs, results|
sum = compute_sum(*inputs)
Result.update_all('sum = #{sum}', "id in (#{results.map(&:id).join(',')})")
end
You can replace result.x, result.y with the actual inputs to the compute_sum function.
EDIT - forgot to put the square brackets around result.x, result.y in the group_by block.
update_all makes an sql query, so any processing you do on the values needs to be in sql. So, you'll need to find the sql function, in whichever DBMS you're using, to add two numbers together. In Postgres, for example, i believe you would do
Sum.update_all(sum: "x + y")
which will generate this sql:
update sums set sum = x + y;
which will calculate the x + y value for each row, and set the sum field to the result.
EDIT - for MariaDB. I've never used this, but a quick google suggests that the sql would be
update sums set sum = sum(x + y);
Try this first, in your sql console, for a single record. If it works, then you can do
Sum.update_all(sum: "sum(x + y)")
in Rails.
EDIT2: there's a lot of things called sum here which is making the example quite confusing. Here's a more generic example.
set col_c to the result of adding col_a and col_b together, in class Foo:
Foo.update_all(col_c: "sum(col_a + col_b)")
I just noticed that i'd copied the (incorrect) Sum.all.update_all from your question. It should just be Sum.update_all - i've updated my answer.