You could use .then()

function getUsers() {
    fetch("https://randomuser.me/api/?results=2")
      .then((results) => {
        return results.json();
      })
      .then((data) => {
        console.log(data);
        // Access your data here
      });
  }
  
getUsers();

And you could also wrap it all in an async function as await must be used inside an async function:

(async function () {
  const users = await fetch("https://randomuser.me/api/?results=2")
    .then((response) => response.json())
    .then((data) => {
      return data;
    });

  console.log({ users });
})();

OR using your original syntax:

async function getUsers() {
  const users = await fetch("https://randomuser.me/api/?results=2");
  return users.json();
}

getUsers().then((data) => console.log(data));