Your problem is before your try, here a, b = map(int, input().split())

The $ is given to int, this fails and raise the invalid literal for int() with base 10: $ which is pretty explicit

try:
    a, b = map(int, input().split())
    print(a//b)
except ZeroDivisionError as e:
    print('Enter code: ', e)
except ValueError as e:
    print('Enter code: ', e)

How do I manually throw/raise an exception in Python?

Use the most specific Exception constructor that semantically fits your issue.

Be specific in your message, e.g.:

raise ValueError('A very specific bad thing happened.')

Don't raise generic exceptions

Avoid raising a generic Exception. To catch it, you'll have to catch all other more specific exceptions that subclass it.

Problem 1: Hiding bugs

raise Exception('I know Python!') # Don't! If you catch, likely to hide bugs.

For example:

def demo_bad_catch():
    try:
        raise ValueError('Represents a hidden bug, do not catch this')
        raise Exception('This is the exception you expect to handle')
    except Exception as error:
        print('Caught this error: ' + repr(error))

>>> demo_bad_catch()
Caught this error: ValueError('Represents a hidden bug, do not catch this',)

Problem 2: Won't catch

And more specific catches won't catch the general exception:

def demo_no_catch():
    try:
        raise Exception('general exceptions not caught by specific handling')
    except ValueError as e:
        print('we will not catch exception: Exception')
 

>>> demo_no_catch()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in demo_no_catch
Exception: general exceptions not caught by specific handling

Best Practices: raise statement

Instead, use the most specific Exception constructor that semantically fits your issue.

raise ValueError('A very specific bad thing happened')

which also handily allows an arbitrary number of arguments to be passed to the constructor:

raise ValueError('A very specific bad thing happened', 'foo', 'bar', 'baz') 

These arguments are accessed by the args attribute on the Exception object. For example:

try:
    some_code_that_may_raise_our_value_error()
except ValueError as err:
    print(err.args)

prints

('message', 'foo', 'bar', 'baz')    

In Python 2.5, an actual message attribute was added to BaseException in favor of encouraging users to subclass Exceptions and stop using args, but the introduction of message and the original deprecation of args has been retracted.

Best Practices: except clause

When inside an except clause, you might want to, for example, log that a specific type of error happened, and then re-raise. The best way to do this while preserving the stack trace is to use a bare raise statement. For example:

logger = logging.getLogger(__name__)

try:
    do_something_in_app_that_breaks_easily()
except AppError as error:
    logger.error(error)
    raise                 # just this!
    # raise AppError      # Don't do this, you'll lose the stack trace!

Don't modify your errors... but if you insist.

You can preserve the stacktrace (and error value) with sys.exc_info(), but this is way more error prone and has compatibility problems between Python 2 and 3, prefer to use a bare raise to re-raise.

To explain - the sys.exc_info() returns the type, value, and traceback.

type, value, traceback = sys.exc_info()

This is the syntax in Python 2 - note this is not compatible with Python 3:

raise AppError, error, sys.exc_info()[2] # avoid this.
# Equivalently, as error *is* the second object:
raise sys.exc_info()[0], sys.exc_info()[1], sys.exc_info()[2]

If you want to, you can modify what happens with your new raise - e.g. setting new args for the instance:

def error():
    raise ValueError('oops!')

def catch_error_modify_message():
    try:
        error()
    except ValueError:
        error_type, error_instance, traceback = sys.exc_info()
        error_instance.args = (error_instance.args[0] + ' <modification>',)
        raise error_type, error_instance, traceback

And we have preserved the whole traceback while modifying the args. Note that this is not a best practice and it is invalid syntax in Python 3 (making keeping compatibility much harder to work around).

>>> catch_error_modify_message()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in catch_error_modify_message
  File "<stdin>", line 2, in error
ValueError: oops! <modification>

In Python 3:

raise error.with_traceback(sys.exc_info()[2])

Again: avoid manually manipulating tracebacks. It's less efficient and more error prone. And if you're using threading and sys.exc_info you may even get the wrong traceback (especially if you're using exception handling for control flow - which I'd personally tend to avoid.)

Python 3, Exception chaining

In Python 3, you can chain Exceptions, which preserve tracebacks:

raise RuntimeError('specific message') from error

Be aware:

• this does allow changing the error type raised, and
• this is not compatible with Python 2.

Deprecated Methods:

These can easily hide and even get into production code. You want to raise an exception, and doing them will raise an exception, but not the one intended!

Valid in Python 2, but not in Python 3 is the following:

raise ValueError, 'message' # Don't do this, it's deprecated!

Only valid in much older versions of Python (2.4 and lower), you may still see people raising strings:

raise 'message' # really really wrong. don't do this.

In all modern versions, this will actually raise a TypeError, because you're not raising a BaseException type. If you're not checking for the right exception and don't have a reviewer that's aware of the issue, it could get into production.

Example Usage

I raise Exceptions to warn consumers of my API if they're using it incorrectly:

def api_func(foo):
    '''foo should be either 'baz' or 'bar'. returns something very useful.'''
    if foo not in _ALLOWED_ARGS:
        raise ValueError('{foo} wrong, use "baz" or "bar"'.format(foo=repr(foo)))

Create your own error types when apropos

"I want to make an error on purpose, so that it would go into the except"

You can create your own error types, if you want to indicate something specific is wrong with your application, just subclass the appropriate point in the exception hierarchy:

class MyAppLookupError(LookupError):
    '''raise this when there's a lookup error for my app'''

and usage:

if important_key not in resource_dict and not ok_to_be_missing:
    raise MyAppLookupError('resource is missing, and that is not ok.')

You are not including all your code as you describe it. Input section should look like this:

while True:
    try:   
        pass_credit=int(input("please enter your credits at pass:"))
        break
    except ValueError as e:
        print ("Bad integer value entered, try again.")

while True:
    try:   
        defer_credit=int(input("please enter your credits at defer:"))
        break
    except ValueError as e:
        print ("Bad integer value entered, try again.")

while True:
    try:   
        fail_credit=int(input("please enter your credits at fail:"))
        break
    except ValueError as e:
        print ("Bad integer value entered, try again.")

print(f"You entered: {pass_credit=}, {defer_credit=}, {fail_credit=}")

In fact, it would be better to capture the value before conversion to provide a better error message, e.g.:

while True:
    try:   
        entry=input("please enter your credits at pass:")
        pass_credit = int(entry)
        break
    except ValueError as e:
        print (f"You entered: {entry}, which is not an integer, try again.")

You stated that you used while and try..except. What did you miss? Comment please.

You should use try...except ValueError, as a ValueError is raised when integer cannot convert something to an integer

choice = [1, 2, 3]


def configselect(choice):
    if choice == 1:
        print("you chose 962")
    elif choice == 2:
        print("you chose Audience")
    elif choice == 3:
        print("you chose mAP")
    
while True:
    try:
        val=int(input("Are you configuring a (1)962, (2)Audience, or (3)mAP? "))
        if val in choice:
            configselect(val)
            break
        else:
            print("Please select either 1,2 or 3")
    except ValueError:
        print('Thats not a valid Number. Please try Again.')