Essentially password_hash uses a one-way function to create a hash that is not reversible. Additionally it adds information to the hash such as the hash algorithm, salt value, iteration count and of course the hash value, this is what is stored. password_verify takes the password and the additional information in the result of password_hash to again create the hash and compares the hash values.

Additionally and importantly password_hash iterates over the hash function to make the process take longer, a good value is 100ms. Thus the best an attacker can do it try passwords to find one that matches and each attempt takes a substantial amount of time. Of course faster computational systems can reduce the ~100ms but it is still costly.

Answer from zaph on Stack Overflow
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Werkzeug
werkzeug.palletsprojects.com › en › stable › utils
Utilities — Werkzeug Documentation (3.1.x)
Securely hash a password for storage. A password can be compared to a stored hash using check_password_hash(). ... scrypt, the default. The parameters are n, r, and p, the default is scrypt:32768:8:1.
🌐
Vulnlab
arz101.medium.com › hackthebox-agile-19a3559ad04a
HackTheBox — Agile - ARZ101 - Medium
August 4, 2023 - On the login page, I tried the default credentials admin:admin for quick win but failed, tried sqli as well but that didn't worked as well
Discussions

python - werkzeug generate_password_hash, is there any point? - Stack Overflow
I see that now the password is stored as a hash in the database and any attacker who sees the hash won't know what the password is without decrypting it. However isn't werkzeug's hashing function a fairly obvious choice for a lot of apps? More on stackoverflow.com
🌐 stackoverflow.com
ralph 3.0 admin login info ?
Django version 1.8.17, using settings ... Using the Werkzeug debugger (http://werkzeug.pocoo.org/) Quit the server with CONTROL-C. * Debugger is active! * Debugger PIN: 176-052-857 · How can I find out default admin login/password info ?... More on github.com
🌐 github.com
1
March 11, 2017
python - Why is the output of werkzeugs `generate_password_hash` not constant? - Stack Overflow
When I run werkzeug.security.generate_password_hash("Same password") (docs) multiple times, the output is different each time. What am I doing wrong? Why is it not constant? More on stackoverflow.com
🌐 stackoverflow.com
python - How can I authorize using werkzeug when accessed via Javascript? - Stack Overflow
I implemented Basic Authorization in Flask. (references this snippet) It works really well. def check_auth(username): user_id = get_user_id(username) return user_id is not None def More on stackoverflow.com
🌐 stackoverflow.com
🌐
Reddit
reddit.com › r/flask › i am getting a werkzeug builderror for logging in to my admin dashboard, even though login is successful
r/flask on Reddit: I am getting a werkzeug BuildError for logging in to my admin dashboard, even though login is successful
September 3, 2023 -

I am getting werkzeug.routing.exceptions.BuildError: Could not build url for endpoint 'login'. Did you mean 'admin.login' instead?
after trying to login to my dashboard. Here's the code:

admin.py

admin_page = Blueprint('admin', __name__, template_folder='templates/admin', static_folder='static/admin')

@admin_page.route('/login/', methods=['GET', 'POST'])
def login():
    form = LoginForm()
    if form.validate_on_submit():
        username = request.form['username']
        password = request.form['password']
        user = User.query.filter_by(username=username).first()
        if user and user.check_password(password):
            login_user(user)
            flash("Login Successful", "success")
            return redirect(request.args.get('next') or url_for('admin.admin_dashboard'))
        else:
            flash("Invalid Credentials", "danger")
            return redirect(url_for('admin.login'))
    return render_template("admin/login.html", form=form)

@admin_page.route('/dashboard/')
@login_required
def admin_dashboard():
    return render_template('dashboard.html')

I tried commenting out the redirect in if user and user.check_password(password) block to check whether I am being logged in, and I was. I tried removing and adding admin in admin.login and admin.dashboard but I am still getting the same error. what should I modify in this code?

🌐
GitHub
github.com › allegro › ralph › issues › 2977
ralph 3.0 admin login info ? · Issue #2977 · allegro/ralph - GitHub
March 11, 2017 - Django version 1.8.17, using settings ... Using the Werkzeug debugger (http://werkzeug.pocoo.org/) Quit the server with CONTROL-C. * Debugger is active! * Debugger PIN: 176-052-857 · How can I find out default admin login/password info ?...
Author   allegro
🌐
Techmonger
techmonger.github.io › 4 › secure-passwords-werkzeug
Secure Passwords in Python With Werkzeug - Tech Monger
November 26, 2017 - In this article we will learn how to implement secure user authentication system using python werkzeug. We will store secure passwords with salted hashes and later we will verify entered user password in plaintext against it's password hash to authenticate user.
🌐
ProgramCreek
programcreek.com › python › example › 82817 › werkzeug.security.generate_password_hash
Python Examples of werkzeug.security.generate_password_hash
def register(): """Render the register page.""" form = RegisterForm(request.form) if request.method == 'POST' and form.validate(): c = mongo.db[app.config['USERS_COLLECTION']] user = { "username": form.username.data, "email": form.email.data, "first_name": form.first_name.data, "last_name": form.last_name.data, "password": generate_password_hash(form.password.data), "groups": [], "first_active": now_time(), "last_active": now_time() } logger.debug("User: %s" % user) user_count = c.count(dict()) if user_count == 0: # Make the first user an administrator user['groups'] = ['admin'] _id = c.insert
Find elsewhere
🌐
Privacera
docs.privacera.com › get-started › diagnostics-tool › change-password-diagnostics-tool.html
Privacera Diagnostics Tool Advanced Configuration Update Password - Privacera Documentation
This document explains how to update the admin credentials for the diagnostics tool's Web UI. Ensure that you have the necessary permissions and access rights to make these changes. ... This guide applies only if basic authentication is enabled. ... The Diagnostic Server requires a hashed password for security purposes. You can generate a hashed password as follows: I. Install the Werkzeug ...
🌐
GitHub
github.com › pallets › werkzeug › blob › main › src › werkzeug › security.py
werkzeug/src/werkzeug/security.py at main · pallets/werkzeug
using :func:`check_password_hash`. · The following methods are supported: · - ``scrypt``, the default. The parameters are ``n``, ``r``, and ``p``, the default · is ``scrypt:32768:8:1``. See :func:`hashlib.scrypt`. - ``pbkdf2``, less secure.
Author   pallets
🌐
Readthedocs
dataflakewsgiwerkzeug.readthedocs.io › en › latest › usage.html
Using this package — dataflake.wsgi.werkzeug 2.3.dev0 documentation
Directory: . Please choose a username and password for the initial user. These will be the credentials you use to initially manage your new Zope instance. Username: admin Password: (enter password) Verify password: (re-enter password) This package has a second entry point to enable the werkzeug ...
🌐
Miguel Grinberg
blog.miguelgrinberg.com › post › the-flask-mega-tutorial-part-v-user-logins › page › 2
The Flask Mega-Tutorial, Part V: User Logins - miguelgrinberg.com
December 3, 2023 - The whole password hashing logic can be implemented as two new methods in the user model: ... from werkzeug.security import generate_password_hash, check_password_hash # ... class User(db.Model): # ...
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Failed to Function
failedtofunction.com › password-management-with-flask
Password Management with Flask
July 16, 2019 - Note the following getter function is marked with the @property decorator and throws an exception. The setter is also decorated to indicate it is the setter for the password property. It uses the Werkzeug module to hash the password, storing the result into password_hash created above.
🌐
GitHub
github.com › dataflake › dataflake.wsgi.werkzeug › blob › master › docs › usage.rst
dataflake.wsgi.werkzeug/docs/usage.rst at master · dataflake/dataflake.wsgi.werkzeug
These will be the credentials you use to initially manage your new Zope instance. Username: admin Password: (enter password) Verify password: (re-enter password) This package has a second entry point to enable the werkzeug debugger.
Author   dataflake
Top answer
1 of 1
75

The password is salted, yes. The salt is added to the password before hashing, to ensure that the hash isn't useable in a rainbow table attack.

Because the salt is randomly generated each time you call the function, the resulting password hash is also different. The returned hash includes the generated salt so that can still correctly verify the password.

Demo:

>>> from werkzeug.security import generate_password_hash
>>> generate_password_hash('foobar')
'pbkdf2:sha1:1000$tYqN0VeL$2ee2568465fa30c1e6680196f8bb9eb0d2ca072d'
>>> generate_password_hash('foobar')
'pbkdf2:sha1:1000$XHj5nlLU$bb9a81bc54e7d6e11d9ab212cd143e768ea6225d'

These two strings differ; but contain enough information to verify the password because the generated salt is included in each:

# pbkdf2:sha1:1000$tYqN0VeL$2ee2568465fa30c1e6680196f8bb9eb0d2ca072d
  ^^^^^^^^^^^^^^^^   salt   ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
      algo info    ^^^^^^^^        actual hash of the password
  (PBKDF2 applied SHA1 1000 times)

Because the random salt is tYqN0VeL for one and XHj5nlLU, the resulting hash is also different.

The foobar password can still be verified against either hash:

>>> from werkzeug.security import check_password_hash
>>> check_password_hash('pbkdf2:sha1:1000$tYqN0VeL$2ee2568465fa30c1e6680196f8bb9eb0d2ca072d', 'foobar')
True
>>> check_password_hash('pbkdf2:sha1:1000$XHj5nlLU$bb9a81bc54e7d6e11d9ab212cd143e768ea6225d', 'foobar')
True

Also see

  • Can you help me understand what a cryptographic “salt” is? (Cryptography.SE)
  • Why is using salt more secure? (Security.SE)
🌐
HackTricks
book.hacktricks.xyz › home › network services pentesting › pentesting web › werkzeug
Werkzeug / Flask Debug - HackTricks
2 days ago - A message regarding the “console locked” scenario is encountered when attempting to access Werkzeug’s debug interface, indicating a requirement for a PIN to unlock the console. The suggestion is made to exploit the console PIN by analyzing the PIN generation algorithm in Werkzeug’s debug initialization file (__init__.py).
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Carsonevans
blog.carsonevans.ca › 2020 › 08 › 02 › storing-passwords-in-flask
Storing Passwords In Flask - Carson's Blog
Werkzeug contains two password related functions in the werkzeug.security module. First is generate_password_hash which is used to create a password hash, and second is check_password_hash which is used to validate a password.
🌐
GitHub
github.com › wdahlenburg › werkzeug-debug-console-bypass
GitHub - wdahlenburg/werkzeug-debug-console-bypass: Werkzeug has a debug console that requires a pin. It's possible to bypass this with an LFI vulnerability or use it as a local privilege escalation vector. · GitHub
A scenario that could come up is that the Flask server is running under a certain user with privileges X. You are a local user on the system with privileges Y. You have the ability to access the same information that Werkzeug uses to generate the PIN for the user running the server.
Starred by 66 users
Forked by 8 users
Languages   Python 85.8% | Dockerfile 14.2%
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Stack Overflow
stackoverflow.com › questions › 11814513 › how-can-i-authorize-using-werkzeug-when-accessed-via-javascript
python - How can I authorize using werkzeug when accessed via Javascript? - Stack Overflow
I implemented Basic Authorization in Flask. (references this snippet) It works really well. def check_auth(username): user_id = get_user_id(username) return user_id is not None def
🌐
YouTube
youtube.com › watch
Password Hashing in Flask Using Werkzeug - YouTube
This video demonstrates how to hash passwords in Flask using Werkzeug, the library Flask is built on.Want to level up your Flask skills? My full course, The ...
Published   July 9, 2016