When programming in Java, you make other classes available to the class you are writing by putting something like this at the top of your source file:
import org.javaguy.coolframework.MyClass;
Or sometimes you 'bulk import' stuff by saying:
import org.javaguy.coolframework.*;
So later in your program when you say:
MyClass mine = new MyClass();
The Java Virtual Machine will know where to find your compiled class.
It would be impractical to have the VM look through every folder on your machine, so you have to provide the VM a list of places to look. This is done by putting folder and jar files on your classpath.
Before we talk about how the classpath is set, let's talk about .class files, packages, and .jar files.
First, let's suppose that MyClass is something you built as part of your project, and it is in a directory in your project called output. The .class file would be at output/org/javaguy/coolframework/MyClass.class (along with every other file in that package). In order to get to that file, your path would simply need to contain the folder 'output', not the whole package structure, since your import statement provides all that information to the VM.
Now let's suppose that you bundle CoolFramework up into a .jar file, and put that CoolFramework.jar into a lib directory in your project. You would now need to put lib/CoolFramework.jar into your classpath. The VM will look inside the jar file for the org/javaguy/coolframework part, and find your class.
So, classpaths contain:
- JAR files, and
- Paths to the top of package hierarchies.
How do you set your classpath?
The first way everyone seems to learn is with environment variables. On a unix machine, you can say something like:
export CLASSPATH=/home/myaccount/myproject/lib/CoolFramework.jar:/home/myaccount/myproject/output/
On a Windows machine you have to go to your environment settings and either add or modify the value that is already there.
The second way is to use the -cp parameter when starting Java, like this:
java -cp "/home/myaccount/myproject/lib/CoolFramework.jar:/home/myaccount/myproject/output/" MyMainClass
A variant of this is the third way which is often done with a .sh or .bat file that calculates the classpath and passes it to Java via the -cp parameter.
There is a "gotcha" with all of the above. On most systems (Linux, Mac OS, UNIX, etc) the colon character (:) is the classpath separator. On Windows the separator is the semicolon (;)
So what's the best way to do it?
Setting stuff globally via environment variables is bad, generally for the same kinds of reasons that global variables are bad. You change the CLASSPATH environment variable so one program works, and you end up breaking another program.
The -cp is the way to go. I generally make sure my CLASSPATH environment variable is an empty string where I develop, whenever possible, so that I avoid global classpath issues (some tools aren't happy when the global classpath is empty though - I know of two common, mega-thousand dollar licensed J2EE and Java servers that have this kind of issue with their command-line tools).
When programming in Java, you make other classes available to the class you are writing by putting something like this at the top of your source file:
import org.javaguy.coolframework.MyClass;
Or sometimes you 'bulk import' stuff by saying:
import org.javaguy.coolframework.*;
So later in your program when you say:
MyClass mine = new MyClass();
The Java Virtual Machine will know where to find your compiled class.
It would be impractical to have the VM look through every folder on your machine, so you have to provide the VM a list of places to look. This is done by putting folder and jar files on your classpath.
Before we talk about how the classpath is set, let's talk about .class files, packages, and .jar files.
First, let's suppose that MyClass is something you built as part of your project, and it is in a directory in your project called output. The .class file would be at output/org/javaguy/coolframework/MyClass.class (along with every other file in that package). In order to get to that file, your path would simply need to contain the folder 'output', not the whole package structure, since your import statement provides all that information to the VM.
Now let's suppose that you bundle CoolFramework up into a .jar file, and put that CoolFramework.jar into a lib directory in your project. You would now need to put lib/CoolFramework.jar into your classpath. The VM will look inside the jar file for the org/javaguy/coolframework part, and find your class.
So, classpaths contain:
- JAR files, and
- Paths to the top of package hierarchies.
How do you set your classpath?
The first way everyone seems to learn is with environment variables. On a unix machine, you can say something like:
export CLASSPATH=/home/myaccount/myproject/lib/CoolFramework.jar:/home/myaccount/myproject/output/
On a Windows machine you have to go to your environment settings and either add or modify the value that is already there.
The second way is to use the -cp parameter when starting Java, like this:
java -cp "/home/myaccount/myproject/lib/CoolFramework.jar:/home/myaccount/myproject/output/" MyMainClass
A variant of this is the third way which is often done with a .sh or .bat file that calculates the classpath and passes it to Java via the -cp parameter.
There is a "gotcha" with all of the above. On most systems (Linux, Mac OS, UNIX, etc) the colon character (:) is the classpath separator. On Windows the separator is the semicolon (;)
So what's the best way to do it?
Setting stuff globally via environment variables is bad, generally for the same kinds of reasons that global variables are bad. You change the CLASSPATH environment variable so one program works, and you end up breaking another program.
The -cp is the way to go. I generally make sure my CLASSPATH environment variable is an empty string where I develop, whenever possible, so that I avoid global classpath issues (some tools aren't happy when the global classpath is empty though - I know of two common, mega-thousand dollar licensed J2EE and Java servers that have this kind of issue with their command-line tools).
Think of it as Java's answer to the PATH environment variable - OSes search for EXEs on the PATH, Java searches for classes and packages on the classpath.
Trying to understand classpath file
What exactly is the classpath? I don't fully get it and only know that it's akin to the PATH variable in Linux.
.classpath file in Java related to Java or Eclipse - Stack Overflow
java - What's in an Eclipse .classpath/.project file? - Stack Overflow
When programming in Java, you make other classes available to the class you are writing by putting something like this at the top of your source file:
import org.javaguy.coolframework.MyClass;
Or sometimes you 'bulk import' stuff by saying:
import org.javaguy.coolframework.*;
So later in your program when you say:
MyClass mine = new MyClass();
The Java Virtual Machine will know where to find your compiled class.
It would be impractical to have the VM look through every folder on your machine, so you have to provide the VM a list of places to look. This is done by putting folder and jar files on your classpath.
Before we talk about how the classpath is set, let's talk about .class files, packages, and .jar files.
First, let's suppose that MyClass is something you built as part of your project, and it is in a directory in your project called output. The .class file would be at output/org/javaguy/coolframework/MyClass.class (along with every other file in that package). In order to get to that file, your path would simply need to contain the folder 'output', not the whole package structure, since your import statement provides all that information to the VM.
Now let's suppose that you bundle CoolFramework up into a .jar file, and put that CoolFramework.jar into a lib directory in your project. You would now need to put lib/CoolFramework.jar into your classpath. The VM will look inside the jar file for the org/javaguy/coolframework part, and find your class.
So, classpaths contain:
- JAR files, and
- Paths to the top of package hierarchies.
How do you set your classpath?
The first way everyone seems to learn is with environment variables. On a unix machine, you can say something like:
export CLASSPATH=/home/myaccount/myproject/lib/CoolFramework.jar:/home/myaccount/myproject/output/
On a Windows machine you have to go to your environment settings and either add or modify the value that is already there.
The second way is to use the -cp parameter when starting Java, like this:
java -cp "/home/myaccount/myproject/lib/CoolFramework.jar:/home/myaccount/myproject/output/" MyMainClass
A variant of this is the third way which is often done with a .sh or .bat file that calculates the classpath and passes it to Java via the -cp parameter.
There is a "gotcha" with all of the above. On most systems (Linux, Mac OS, UNIX, etc) the colon character (:) is the classpath separator. On Windows the separator is the semicolon (;)
So what's the best way to do it?
Setting stuff globally via environment variables is bad, generally for the same kinds of reasons that global variables are bad. You change the CLASSPATH environment variable so one program works, and you end up breaking another program.
The -cp is the way to go. I generally make sure my CLASSPATH environment variable is an empty string where I develop, whenever possible, so that I avoid global classpath issues (some tools aren't happy when the global classpath is empty though - I know of two common, mega-thousand dollar licensed J2EE and Java servers that have this kind of issue with their command-line tools).
What is the purpose of setting a classpath in Java?
Can classpath include multiple directories or JAR files?
When would I use a relative path in the classpath?
I just started learning Java so we have a study group where we are supposed to create a simple desktop application using Eclipse IDE and WindowBuilder.
I created the base project and then proceeded to push it to the shared repository. The rest of the people in the team tried executing the base project without success, while I could run it without any issues.
After a while, one of the members realized there is a problem with the classpatch file:
<?xml version="1.0" encoding="UTF-8"?>
<classpath> <classpathentry kind="src" path="src"/> <classpathentry kind="con" path="org.eclipse.jdt.launching.JRE\_CONTAINER"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/com.ibm.icu\_74.2.0.jar" sourcepath="/snap/eclipse/85/plugins/com.ibm.icu\_74.2.0.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/jakarta.annotation-api\_2.1.1.jar" sourcepath="/snap/eclipse/85/plugins/jakarta.annotation-api\_2.1.1.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.core.commands\_3.12.0.v20240214-1640.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.core.commands\_3.12.0.v20240214-1640.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.core.runtime\_3.31.0.v20240215-1631.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.core.runtime\_3.31.0.v20240215-1631.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.e4.ui.di\_1.5.300.v20240116-1723.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.e4.ui.di\_1.5.300.v20240116-1723.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.equinox.common\_3.19.0.v20240214-0846.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.equinox.common\_3.19.0.v20240214-0846.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.equinox.registry\_3.12.0.v20240213-1057.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.equinox.registry\_3.12.0.v20240213-1057.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.jface\_3.33.0.v20240214-1640.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.jface\_3.33.0.v20240214-1640.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.jface.text\_3.25.0.v20240207-1054.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.jface.text\_3.25.0.v20240207-1054.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.osgi\_3.19.0.v20240213-1246.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.osgi\_3.19.0.v20240213-1246.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.swt.gtk.linux.x86\_64\_3.125.0.v20240227-1638.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.swt.gtk.linux.x86\_64\_3.125.0.v20240227-1638.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.text\_3.14.0.v20240207-1054.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.text\_3.14.0.v20240207-1054.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.ui.forms\_3.13.200.v20240108-1539.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.ui.forms\_3.13.200.v20240108-1539.jar"/> <classpathentry kind="lib" path="/snap/eclipse/85/plugins/org.eclipse.ui.workbench\_3.131.100.v20240221-2107.jar" sourcepath="/snap/eclipse/85/plugins/org.eclipse.ui.workbench\_3.131.100.v20240221-2107.jar"/> <classpathentry kind="output" path="bin"/> </classpath>
This is making reference to several libs which exist only in my notebok, where I am using Ubuntu. They are trying to run it in Windows.
Is it not kind of stupid to refer to these libs this way? I am still trying to understanc why Java would make reference to these libs assuming all of us would be using Ubuntu? Nobody else in my team has the snap folder :/
Could you please help me understand what is going on? How can we fix it?
I tried looking for some videos explaining the classpath file but no luck so far.
Thank you :(
I read this:
In Java, the term "classpath" refers to a parameter that specifies a set of directories or JAR (Java Archive) files where the Java Virtual Machine (JVM) and Java compiler should look for classes and resources when running or compiling Java applications
But where does this classpath comes into existence? If you for example have a completely vanilla project with some source code, and want to compile it manually with javac, does this notion of class path exist, for example?
How does it work in the context of build automation tools like Maven?And in an intelliJ project, for example, where can I find the class path and how does it work relatively to the project?
I've read a lot about what it does, but not what it exactly is and I would really appreciate some clarification!
Edit: I tried to look at the docs (oracle for example), but even there it's all kind of vague.
.class files are related to Java.
You write your code in java, it is compiled by javac into bytecode. The bytecode is stored in the .class files, and further interpreted by the Java virtual machine (JVM).
About .classpath on Wikipedia:
Similar to the classic dynamic loading behavior, when executing Java programs, the Java Virtual Machine finds and loads classes lazily (it loads the bytecode of a class only when this class is first used). The .classpath tells Java where to look in the file-system for files defining these classes.
So the .classpath mechanism is related to Java, and is handled by eclipse thanks to the .classpath file.
Hope it helps :)
It's java bytecode in .class file. Whenever you compile the javacode, you will get .class file per java class. Behind the scenes, Eclipse incrementally does compile your java code in the project and hence you don't end up manually compiling our java code.
Eclipse is a runtime environment for plugins. Virtually everything you see in Eclipse is the result of plugins installed on Eclipse, rather than Eclipse itself.
The .project file is maintained by the core Eclipse platform, and its goal is to describe the project from a generic, plugin-independent Eclipse view. What's the project's name? what other projects in the workspace does it refer to? What are the builders that are used in order to build the project? (remember, the concept of "build" doesn't pertain specifically to Java projects, but also to other types of projects)
The .classpath file is maintained by Eclipse's JDT feature (feature = set of plugins). JDT holds multiple such "meta" files in the project (see the .settings directory inside the project); the .classpath file is just one of them. Specifically, the .classpath file contains information that the JDT feature needs in order to properly compile the project: the project's source folders (that is, what to compile); the output folders (where to compile to); and classpath entries (such as other projects in the workspace, arbitrary JAR files on the file system, and so forth).
Blindly copying such files from one machine to another may be risky. For example, if arbitrary JAR files are placed on the classpath (that is, JAR files that are located outside the workspace and are referred-to by absolute path naming), the .classpath file is rendered non-portable and must be modified in order to be portable. There are certain best practices that can be followed to guarantee .classpath file portability.
Complete reference is not available for the mentioned files, as they are extensible by various plug-ins.
Basically, .project files store project-settings, such as builder and project nature settings, while .classpath files define the classpath to use during running. The classpath files contains src and target entries that correspond with folders in the project; the con entries are used to describe some kind of "virtual" entries, such as the JVM libs or in case of eclipse plug-ins dependencies (normal Java project dependencies are displayed differently, using a special src entry).