Am I missing something?
Doesn't this hypothetical code
while(rowIndex >= dataColLinker.size()) {
dataColLinker.add(value);
} else {
dataColLinker.set(rowIndex, value);
}
mean the same thing as this?
while(rowIndex >= dataColLinker.size()) {
dataColLinker.add(value);
}
dataColLinker.set(rowIndex, value);
or this?
if (rowIndex >= dataColLinker.size()) {
do {
dataColLinker.add(value);
} while(rowIndex >= dataColLinker.size());
} else {
dataColLinker.set(rowIndex, value);
}
(The latter makes more sense ... I guess). Either way, it is obvious that you can rewrite the loop so that the "else test" is not repeated inside the loop ... as I have just done.
FWIW, this is most likely a case of premature optimization. That is, you are probably wasting your time optimizing code that doesn't need to be optimized:
For all you know, the JIT compiler's optimizer may have already moved the code around so that the "else" part is no longer in the loop.
Even if it hasn't, the chances are that the particular thing you are trying to optimize is not a significant bottleneck ... even if it might be executed 600,000 times.
My advice is to forget this problem for now. Get the program working. When it is working, decide if it runs fast enough. If it doesn't then profile it, and use the profiler output to decide where it is worth spending your time optimizing.
Answer from Stephen C on Stack OverflowAm I missing something?
Doesn't this hypothetical code
while(rowIndex >= dataColLinker.size()) {
dataColLinker.add(value);
} else {
dataColLinker.set(rowIndex, value);
}
mean the same thing as this?
while(rowIndex >= dataColLinker.size()) {
dataColLinker.add(value);
}
dataColLinker.set(rowIndex, value);
or this?
if (rowIndex >= dataColLinker.size()) {
do {
dataColLinker.add(value);
} while(rowIndex >= dataColLinker.size());
} else {
dataColLinker.set(rowIndex, value);
}
(The latter makes more sense ... I guess). Either way, it is obvious that you can rewrite the loop so that the "else test" is not repeated inside the loop ... as I have just done.
FWIW, this is most likely a case of premature optimization. That is, you are probably wasting your time optimizing code that doesn't need to be optimized:
For all you know, the JIT compiler's optimizer may have already moved the code around so that the "else" part is no longer in the loop.
Even if it hasn't, the chances are that the particular thing you are trying to optimize is not a significant bottleneck ... even if it might be executed 600,000 times.
My advice is to forget this problem for now. Get the program working. When it is working, decide if it runs fast enough. If it doesn't then profile it, and use the profiler output to decide where it is worth spending your time optimizing.
I don't see why there is a encapsulation of a while...
Use
//Use the appropriate start and end...
for(int rowIndex = 0, e = 65536; i < e; ++i){
if(rowIndex >= dataColLinker.size()) {
dataColLinker.add(value);
} else {
dataColLinker.set(rowIndex, value);
}
}
java - While-loop(if else statement) - Stack Overflow
Help with a While Loop (Java)
[Java] Use if/else statement nested in a while loop?
While loops can have an else statement!
Videos
The closest Java equivalent is to explicitly keep track of whether you exited the loop with a break... but you don't actually have a break in your code, so using a while-else was pointless in the first place.
For Java folks (and Python folks) who don't know what Python's while-else does, an else clause on a while loop executes if the loop ends without a break. Another way to think about it is that it executes if the while condition is false, just like with an if statement.
A while-else that actually had a break:
while whatever():
if whatever_else():
break
do_stuff()
else:
finish_up()
could be translated to
boolean noBreak = true;
while (whatever()) {
if (whateverElse()) {
noBreak = false;
break;
}
doStuff();
}
if (noBreak) {
finishUp();
}
Just use one more if statement:
if (temp.nextToABeeper())
// pick beer
} else {
while (temp.frontIsClear()) { /* your code */ }
}
Or:
if (temp.frontIsClear())
while (temp.frontIsClear()) { /* your code */ }
} else if (temp.nextToABeeper()) {
// pick beer
}
**SOLVED**
Thanks lurgi!
Hello, and thank you for your time. I am a student rather new to Java, and programming as a whole.
I am trying to make it so that after the 'else' statement, the loop checks the condition for the 'while' booleans again. I have been at this for around two hours, to no avail. Did I write the entirety of the code incorrectly? Thank you again for your time.
String choice1 = input.nextLine();
choice1 = choice1.toUpperCase();
char truInput1 = choice1.charAt(0);
while (truInput1 != 'R' || truInput1 != 'Q') {
if (truInput1 == 'R') {
System.out.println("placeholder1");
}
else if (truInput1 == 'Q') {
System.out.println("exit placeholder");
System.exit(0);
}
else {
System.out.println("incorrect placeholder");
choice1 = input.nextLine();
choice1 = choice1.toUpperCase();
}
}
Maybe I'm the only one who didn't know this, but you can put an else statement after a while loop which will be used if the while loop is never entered. I found this out on the Leetcode problem of the day for today when I tried putting an else after my while loop, mostly expecting an error but typing because it's what I wanted the code to do, and it ran! The code I used is below. I know there are more optimal solutions, but I'm happy with what I learned today.
class Solution:
def dailyTemperatures(self, temperatures: List[int]) -> List[int]:
n = len(temperatures)
answers = [0] * n
stack = []
for i in range(n):
while len(stack) > 0 and temperatures[i] > stack[-1][1]:
answers[stack[-1][0]] = i - stack[-1][0]
stack.pop()
else:
stack.append([i, temperatures[i]])
if len(stack) == 0:
stack.append([i, temperatures[i]])
return answers