You can do this with the XlsxWriter Worksheet write_url() method using the internal: URI. See the XlsxWriter docs on write_url().
You can do this with the XlsxWriter Worksheet write_url() method using the internal: URI. See the XlsxWriter docs on write_url().
To put a "Friendly Name" in the hyperlink use the string argument of write_url() method. For example, I did the following after setting the variable sheet_name, which in this case is both the name of the sheet to link to and the friendly name:
write_url(row, col, f"internal:'{sheet_name}'!A1", string=sheet_name)
I found a way to do it.
Assuming one .xlsx file named 'workbookEx.xlsx' with two sheets named 'sheet1' and 'sheet2' and needing a link from one cell(A1) of the 'sheet1' to another cell(E5) of the 'sheet2':
from openpyxl import load_workbook
wb = load_workbook(workbookEx.xlsx)
ws = wb.get_sheet_by_name("sheet1")
link = "workbookEx.xlsx#sheet2!E5"
ws.cell(row=1, column=1).hyperlink = (link)
The secret was the "#", Excel do not shows you but it uses the '#' for same file links, I just had to copy a same file link created in Excel to a Word document to see the '#'.
It is also possible to omit the filename, i.e. to link against a sheet of the active document just use: _cell.hyperlink = '#sheetName!A1'.
To name the link you just created, just set the cell value to the desired string: _cell.value = 'Linkname'.
As an addendum to Marcus.Luck's answer, if wanting to use Excel's built-in hyperlink function directly, you may need to format as:
'=HYPERLINK("{}", "{}")'.format(link, "Link Name")
Without this formatting, the file didn't open for me without needing repair, which removed the cell values when clicking the links.
e.g. ws.cell(row=1, column=1).value = '=HYPERLINK("{}", "{}")'.format(link, "Link Name")

