I finally opted for the quick and dirty trick of replacing the escaped slashes in the serialized string before sending it to the server. Luckily, JSONObject also escapes backslashes, so i must also unscape them. Now if I wanted to send "\ /" intentionally the escaped string would be "\\/" and the result of replacing is the original string as intended.
Answer from Mister Smith on Stack OverflowI finally opted for the quick and dirty trick of replacing the escaped slashes in the serialized string before sending it to the server. Luckily, JSONObject also escapes backslashes, so i must also unscape them. Now if I wanted to send "\ /" intentionally the escaped string would be "\\/" and the result of replacing is the original string as intended.
jsonObjSend.toString().replace("\\\\","")
Worked for me. A bit dirty trick but seems no other solution.
I'm appalled by the presence of highly-upvoted misinformation on such a highly-viewed question about a basic topic.
JSON strings cannot be quoted with single quotes. The various versions of the spec (the original by Douglas Crockford, the ECMA version, and the IETF version) all state that strings must be quoted with double quotes. This is not a theoretical issue, nor a matter of opinion as the accepted answer currently suggests; any JSON parser in the real world will error out if you try to have it parse a single-quoted string.
Crockford's and ECMA's version even display the definition of a string using a pretty picture, which should make the point unambiguously clear:

The pretty picture also lists all of the legitimate escape sequences within a JSON string:
\"\\\/\b\f\n\r\t\ufollowed by four-hex-digits
Note that, contrary to the nonsense in some other answers here, \' is never a valid escape sequence in a JSON string. It doesn't need to be, because JSON strings are always double-quoted.
Finally, you shouldn't normally have to think about escaping characters yourself when programatically generating JSON (though of course you will when manually editing, say, a JSON-based config file). Instead, form the data structure you want to encode using whatever native map, array, string, number, boolean, and null types your language has, and then encode it to JSON with a JSON-encoding function. Such a function is probably built into whatever language you're using, like JavaScript's JSON.stringify, PHP's json_encode, or Python's json.dumps. If you're using a language that doesn't have such functionality built in, you can probably find a JSON parsing and encoding library to use. If you simply use language or library functions to convert things to and from JSON, you'll never even need to know JSON's escaping rules. This is what the misguided question asker here ought to have done.
A JSON string must be double-quoted, according to the specs, so you don't need to escape '.
If you have to use special character in your JSON string, you can escape it using \ character.
See this list of special character used in JSON :
\b Backspace (ascii code 08)
\f Form feed (ascii code 0C)
\n New line
\r Carriage return
\t Tab
\" Double quote
\\ Backslash character
However, even if it is totally contrary to the spec, the author could use \'.
This is bad because :
- It IS contrary to the specs
- It is no-longer JSON valid string
But it works, as you want it or not.
For new readers, always use a double quotes for your json strings.
Take your JSON and .stringify() it. Then use the .replace() method and replace all occurrences of \n with \\n.
EDIT:
As far as I know of, there are no well-known JS libraries for escaping all special characters in a string. But, you could chain the .replace() method and replace all of the special characters like this:
var myJSONString = JSON.stringify(myJSON);
var myEscapedJSONString = myJSONString.replace(/\\n/g, "\\n")
.replace(/\\'/g, "\\'")
.replace(/\\"/g, '\\"')
.replace(/\\&/g, "\\&")
.replace(/\\r/g, "\\r")
.replace(/\\t/g, "\\t")
.replace(/\\b/g, "\\b")
.replace(/\\f/g, "\\f");
// myEscapedJSONString is now ready to be POST'ed to the server.
But that's pretty nasty, isn't it? Enter the beauty of functions, in that they allow you to break code into pieces and keep the main flow of your script clean, and free of 8 chained .replace() calls. So let's put that functionality into a function called, escapeSpecialChars(). Let's go ahead and attach it to the prototype chain of the String object, so we can call escapeSpecialChars() directly on String objects.
Like so:
String.prototype.escapeSpecialChars = function() {
return this.replace(/\\n/g, "\\n")
.replace(/\\'/g, "\\'")
.replace(/\\"/g, '\\"')
.replace(/\\&/g, "\\&")
.replace(/\\r/g, "\\r")
.replace(/\\t/g, "\\t")
.replace(/\\b/g, "\\b")
.replace(/\\f/g, "\\f");
};
Once we have defined that function, the main body of our code is as simple as this:
var myJSONString = JSON.stringify(myJSON);
var myEscapedJSONString = myJSONString.escapeSpecialChars();
// myEscapedJSONString is now ready to be POST'ed to the server
As per user667073 suggested, except reordering the backslash replacement first, and fixing the quote replacement
escape = function (str) {
return str
.replace(/[\\]/g, '\\\\')
.replace(/[\"]/g, '\\\"')
.replace(/[\/]/g, '\\/')
.replace(/[\b]/g, '\\b')
.replace(/[\f]/g, '\\f')
.replace(/[\n]/g, '\\n')
.replace(/[\r]/g, '\\r')
.replace(/[\t]/g, '\\t');
};
Ideally, find a JSON library in your language that you can feed some appropriate data structure to, and let it worry about how to escape things. It'll keep you much saner. If for whatever reason you don't have a library in your language, you don't want to use one (I wouldn't suggest this¹), or you're writing a JSON library, read on.
Escape it according to the RFC. JSON is pretty liberal: The only characters you must escape are \, ", and control codes (anything less than U+0020).
This structure of escaping is specific to JSON. You'll need a JSON specific function. All of the escapes can be written as \uXXXX where XXXX is the UTF-16 code unit¹ for that character. There are a few shortcuts, such as \\, which work as well. (And they result in a smaller and clearer output.)
For full details, see the RFC.
¹JSON's escaping is built on JS, so it uses \uXXXX, where XXXX is a UTF-16 code unit. For code points outside the BMP, this means encoding surrogate pairs, which can get a bit hairy. (Or, you can just output the character directly, since JSON's encoded for is Unicode text, and allows these particular characters.)
Extract From Jettison:
public static String quote(String string) {
if (string == null || string.length() == 0) {
return "\"\"";
}
char c = 0;
int i;
int len = string.length();
StringBuilder sb = new StringBuilder(len + 4);
String t;
sb.append('"');
for (i = 0; i < len; i += 1) {
c = string.charAt(i);
switch (c) {
case '\\':
case '"':
sb.append('\\');
sb.append(c);
break;
case '/':
// if (b == '<') {
sb.append('\\');
// }
sb.append(c);
break;
case '\b':
sb.append("\\b");
break;
case '\t':
sb.append("\\t");
break;
case '\n':
sb.append("\\n");
break;
case '\f':
sb.append("\\f");
break;
case '\r':
sb.append("\\r");
break;
default:
if (c < ' ') {
t = "000" + Integer.toHexString(c);
sb.append("\\u" + t.substring(t.length() - 4));
} else {
sb.append(c);
}
}
}
sb.append('"');
return sb.toString();
}