Try this:
[(i, j) for i, j in enumerate(mylist)]
You need to put i,j inside a tuple for the list comprehension to work. Alternatively, given that enumerate() already returns a tuple, you can return it directly without unpacking it first:
[pair for pair in enumerate(mylist)]
Either way, the result that gets returned is as expected:
> [(0, 'a'), (1, 'b'), (2, 'c'), (3, 'd')]
Answer from Óscar López on Stack OverflowPython using enumerate inside list comprehension - Stack Overflow
What does enumerate do in python? : r/learnpython
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About iterating over a list of tuples
Try this:
[(i, j) for i, j in enumerate(mylist)]
You need to put i,j inside a tuple for the list comprehension to work. Alternatively, given that enumerate() already returns a tuple, you can return it directly without unpacking it first:
[pair for pair in enumerate(mylist)]
Either way, the result that gets returned is as expected:
> [(0, 'a'), (1, 'b'), (2, 'c'), (3, 'd')]
Just to be really clear, this has nothing to do with enumerate and everything to do with list comprehension syntax.
This list comprehension returns a list of tuples:
[(i,j) for i in range(3) for j in 'abc']
this a list of dicts:
[{i:j} for i in range(3) for j in 'abc']
a list of lists:
[[i,j] for i in range(3) for j in 'abc']
a syntax error:
[i,j for i in range(3) for j in 'abc']
Which is inconsistent (IMHO) and confusing with dictionary comprehensions syntax:
>>> {i:j for i,j in enumerate('abcdef')}
{0: 'a', 1: 'b', 2: 'c', 3: 'd', 4: 'e', 5: 'f'}
And a set of tuples:
>>> {(i,j) for i,j in enumerate('abcdef')}
set([(0, 'a'), (4, 'e'), (1, 'b'), (2, 'c'), (5, 'f'), (3, 'd')])
As Óscar López stated, you can just pass the enumerate tuple directly:
>>> [t for t in enumerate('abcdef') ]
[(0, 'a'), (1, 'b'), (2, 'c'), (3, 'd'), (4, 'e'), (5, 'f')]