float range python example

stackoverflow.com › questions › 7267226 › range-for-floats

You can either use:

[x / 10.0 for x in range(5, 50, 15)]

or use lambda / map:

map(lambda x: x/10.0, range(5, 50, 15))

Answer from Grzegorz Rożniecki on Stack Overflow

Stack Overflow

stackoverflow.com › questions › 7267226 › range-for-floats

python - range() for floats - Stack Overflow

Top answer

1 of 16

185

You can either use:

[x / 10.0 for x in range(5, 50, 15)]

or use lambda / map:

map(lambda x: x/10.0, range(5, 50, 15))

2 of 16

117

I don't know a built-in function, but writing one like this shouldn't be too complicated.

def frange(x, y, jump):
  while x < y:
    yield x
    x += jump

---

As the comments mention, this could produce unpredictable results like:

>>> list(frange(0, 100, 0.1))[-1]
99.9999999999986

To get the expected result, you can use one of the other answers in this question, or as @Tadhg mentioned, you can use decimal.Decimal as the jump argument. Make sure to initialize it with a string rather than a float.

>>> import decimal
>>> list(frange(0, 100, decimal.Decimal('0.1')))[-1]
Decimal('99.9')

Or even:

import decimal

def drange(x, y, jump):
  while x < y:
    yield float(x)
    x += decimal.Decimal(jump)

And then:

>>> list(drange(0, 100, '0.1'))[-1]
99.9

[editor's not: if you only use positive jump and integer start and stop (x and y) , this works fine. For a more general solution see here.]

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Python range() with float values - Spark By {Examples}

May 31, 2024 - Example 2: Let’s generate float values by specifying the num parameter. import numpy as np # Using np.linspace() with num parameter for i in np.linspace(1.5, 5.5,num=5): print(i, end=', ') # Output: # 1.5, 2.5, 3.5, 4.5, 5.5, We specified the num parameter and set it to 5. So only 5 values are generated within the given range. You have learned that the Python range() function won’t support generating the float values.

Discussions

python - How do I use a decimal step value for range()? - Stack Overflow

I did a xfrange function without the float precision problems referred above. Check it out ;) stackoverflow.com/questions/477486/… 2013-12-12T17:05:29.957Z+00:00 ... You're accumulating rounding errors. Please use this instead: ` i = 0; r = start while r < stop: i += 1; r = start + i * step; yield r` 2016-04-11T11:56:21.267Z+00:00 ... This is from pythoncentral.io/pythons-range... More on stackoverflow.com

stackoverflow.com

float numbers with range () function

Yes, range(0, 101) literally gives the integers from 0 to 100. If you want to know if a number is between two values, use a chained comparison: while 0 <= score < 101: Although note you shouldn't get an actual error, just a False. What exact error message did you see? More on reddit.com

r/learnpython

April 19, 2022

Float contained in range - Ideas - Discussions on Python.org

I have found that checking if a float number falls inside a range() doesn’t work, always giving False: >>> 1.0 in range (0, 2) True >>> 1.5 in range (0, 2) False I can understand that range() can only accept integer values, but checking if it contains a float number should works. More on discuss.python.org

discuss.python.org

September 7, 2023

How to step by floats in a range function?

A somewhat “hacky” way to accomplish this using range directly is by multiplying start/end/step by a power of 10 so they’re all integers, then dividing by that same power in your loop. Do note that range doesn’t include the right endpoint. e.g. for degrees in range(0,3600,225): print(degrees/10) You could also form the step-size on your own and use range to get a multiple of it. E.g. if I wanted to cut [1,2] into 17 pieces, I could do for multiple in range(18): x = 1+(multiple/17) print(x) or just use numpy.linspace. More on reddit.com

r/learnpython

November 11, 2020

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