same way you did the fill in, but reverse the indexes:

>>> for j in range(columns):
...     for i in range(rows):
...        print mylist[i][j],
... 
0,0 1,0 2,0 0,1 1,1 2,1
>>> 

You need to tell us something about this: dataset = datas.values

It's probably a 2d array, since it derives from a load of a csv. But what shape and dtype? Maybe even a sample of the array.

Is that the data argument in the function?

What are blackKings and values? You treat them like lists (with append).

for i in data:
    if data[i][39] == 1:

This doesn't make sense. for i in data, if data is 2d, i is the the first row, then the second row, etc. If you want i to in an index, you use something like

for i in range(data.shape[0]):

2d array indexing is normally done with data[i,39].

But in your case data[i][39] is probably an array.

Anytime you use an array in a if statement, you'll get this ValueError, because there are multiple values.

If i were proper indexes, then data[i,39] would be a single value.

To illustrate:

In [41]: data=np.random.randint(0,4,(4,4))
In [42]: data
Out[42]: 
array([[0, 3, 3, 2],
       [2, 1, 0, 2],
       [3, 2, 3, 1],
       [1, 3, 3, 3]])
In [43]: for i in data:
    ...:     print('i',i)
    ...:     print('data[i]',data[i].shape)
    ...:     
i [0 3 3 2]            # 1st row
data[i] (4, 4)
i [2 1 0 2]            # a 4d array
data[i] (4, 4)
...

Here i is a 4 element array; using that to index data[i] actually produces a 4 dimensional array; it isn't selecting one value, but rather many values.

Instead you need to iterate in one of these ways:

In [46]: for row in data:
    ...:     if row[3]==1:
    ...:         print(row)
[3 2 3 1]
In [47]: for i in range(data.shape[0]):
    ...:     if data[i,3]==1:
    ...:         print(data[i])
[3 2 3 1]

To debug a problem like this you need to look at intermediate values, and especially their shapes. Don't just assume. Check!

Basically, it's nested for loop. You can use list comprehension to do that.

matches = [(A.index(a),B.index(b)) for a in A for b in B if len(set(a).intersection(set(b)))]

List items are iterable, no need to get length as they will assign themselves to the first variable with for..in.. loops;

for item in numbers:
    print "In first list: ", item
    for num in item:
        print "    Getting number: ", num

outputs

In first list:  [0, 1, 2, 3, 4]
    Getting number:  0
    Getting number:  1
    Getting number:  2
    Getting number:  3
    Getting number:  4
In first list:  [0, 1, 2, 3, 4]
    Getting number:  0
    Getting number:  1
...