You need to use an ObjectMapper:

ObjectMapper mapper = new ObjectMapper();
JsonFactory factory = mapper.getJsonFactory(); // since 2.1 use mapper.getFactory() instead
JsonParser jp = factory.createJsonParser("{\"k1\":\"v1\"}");
JsonNode actualObj = mapper.readTree(jp);

Further documentation about creating parsers can be found here.

And instead of handling errors in every mapper.readValue(json, Class) you can write a helper class which has another Generic method.

and use

String jsonString = "{\"id\":100,\"firstName\":\"Adam\"}";
Student student = JSONUtils.convertToObject(jsonString, Student.class);

I'm returning null and fancying printing trace & checking null later on. You can handle error cases on your own way.

public class JSONUtils {
    public static String convertToJSON(Object object) {
        ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
        String json;
        try {
            json = ow.writeValueAsString(object);
        } catch (JsonProcessingException e) {
            e.printStackTrace();
            return convertToJSON(e);
        }
        return json;
    }
    
    
    public static <T> T convertToObject(Class<T> clazz, String jsonString) {
        try {
            ObjectMapper mapper = new ObjectMapper();
            return (T) mapper.readValue(jsonString, clazz);
        } catch(Exception e) {
            e.printStackTrace();
            return null;
        }
    }
}

This is not valid JSON, and it is not supported by Jackson; nor is it likely to be supported in future. I would suggest making that a regular JSON String, and then re-parsing on Javascript side if and as necessary.