Use commons-lang NumberUtils.createInteger() method:

CopyNumberUtils.createInteger(null); // null
NumberUtils.createInteger("5"); // 5

null is not a valid representation of integer number. Integer.parseInt() requires that the string be parsed is a vaild representation of integer number.

Integer.parseInt()

  public static int parseInt(String s, int radix)
440                 throws NumberFormatException
441     {
442         if (s == null) {
443             throw new NumberFormatException("null");
444         }

Integer.valueOf(str)] // which inviokes Integer.parseInt(Str) to return an Integer instance.

  public static Integer valueOf(String s) throws NumberFormatException
569     {
570         return new Integer(parseInt(s, 10));
571     }

here is a solution :

int tryParseInt(String value) { 
 try {  
     return Integer.parseInt(value);  
  } catch(NumberFormatException nfe) {  
      // Log exception.
      return 0;
  }  
}

you should catch NumberFormatException instead of exception.

I am sure you are over-complicating the problem, it is a real simple thing to do. Check the code below:

Integer i = null;
System.out.println(i == null ?"":i);

int can't be null, but Integer can. You need to be careful when unboxing null Integers since this can cause a lot of confusion and head scratching!

e.g. this:

int a = object.getA(); // getA returns a null Integer

will give you a NullPointerException, despite object not being null!

To follow up on your question, if you want to indicate the absence of a value, I would investigate java.util.Optional<Integer> or java.util.OptionalInt

parseInt() is just going to throw an exception if the parsing can't complete successfully. You can instead use Integers, the corresponding object type, which makes things a little bit cleaner. So you probably want something closer to:

Integer s = null;

try { 
  s = Integer.valueOf(startField.getText());
}
catch (NumberFormatException e) {
  // ...
}

if (s != null) { ... }

Beware if you do decide to use parseInt()! parseInt() doesn't support good internationalization, so you have to jump through even more hoops:

try {
    NumberFormat nf = NumberFormat.getIntegerInstance(locale);
    nf.setParseIntegerOnly(true);
    nf.setMaximumIntegerDigits(9); // Or whatever you'd like to max out at.

    // Start parsing from the beginning.
    ParsePosition p = new ParsePosition(0);

    int val = format.parse(str, p).intValue();
    if (p.getIndex() != str.length()) {
        // There's some stuff after all the digits are done being processed.
    }

    // Work with the processed value here.
} catch (java.text.ParseFormatException exc) {
    // Something blew up in the parsing.
}

That code will give a NullPointerException when you run it. It's basically equivalent to:

Integer a = null;
int b = a.intValue();

... which makes it clearer that it will indeed fail.

You're not really assigning a null value to an int - you're trying and failing.

It's fine to use null as a value for an Integer; indeed often Integer is used instead of int precisely as a "nullable equivalent`.

An int is not null, it may be 0 if not initialized.

If you want an integer to be able to be null, you need to use Integer instead of int.

Integer id;
String name;

public Integer getId() { return id; }

Besides, the statement if(person.equals(null)) can't be true because if person is null, then a NullPointerException will be thrown. So the correct expression is if (person == null)