Long.MAX_VALUE is 9223372036854775807 (9,223,372,036,854,775,807 or 263-1).

If you were executing your function once per nanosecond, it would still take over 292 years to encounter this situation according to this source.

When that happens, it'll just wrap around to Long.MIN_VALUE which is -9223372036854775808 (-9,223,372,036,854,775,808 or -263) as others have said.

Answer from Krease on Stack Overflow
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Delft Stack
delftstack.com › home › howto › java › long max value in java
Long.MAX_VALUE in Java | Delft Stack
October 30, 2023 - Then, we attempt to add 1 to a. Before performing the addition, we check if the result is less than the original value of a or greater than Long.MAX_VALUE. If this condition is true, it indicates that an overflow has occurred. Otherwise, the addition is within the valid range for long values and no overflow has occurred. ... Overflow detected! In Java, attempting to add 1 to the Long.MAX_VALUE constant will indeed result in overflow, causing the value to wrap around to the lowest possible long value, which is -9223372036854775808.
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Oracle
docs.oracle.com › javase › tutorial › java › nutsandbolts › datatypes.html
Primitive Data Types (The Java™ Tutorials > Learning the Java Language > Language Basics)
The signed long has a minimum value of -263 and a maximum value of 263-1. In Java SE 8 and later, you can use the long data type to represent an unsigned 64-bit long, which has a minimum value of 0 and a maximum value of 264-1. Use this data type when you need a range of values wider than those ...
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Stack Overflow
stackoverflow.com › questions › 15505515 › java-long-primitive-type-maximum-limit
Java Long primitive type maximum limit - Stack Overflow
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Long.MAX_VALUE is 9223372036854775807 (9,223,372,036,854,775,807 or 263-1).

If you were executing your function once per nanosecond, it would still take over 292 years to encounter this situation according to this source.

When that happens, it'll just wrap around to Long.MIN_VALUE which is -9223372036854775808 (-9,223,372,036,854,775,808 or -263) as others have said.

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It will overflow and wrap around to Long.MIN_VALUE.

Its not too likely though. Even if you increment 1,000,000 times per second it will take about 300,000 years to overflow.

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GoLinuxCloud
golinuxcloud.com › home › java › long.max_value & long.min_value in java (exact values + examples)
Long.MAX_VALUE & Long.MIN_VALUE in Java (Exact Values + Examples) | GoLinuxCloud
January 16, 2022 - It is 19 digits long (9,223,372,036,854,775,807). No. Java is platform-independent. A long is strictly 64-bit on all JVM architectures. Long.MAX_VALUE and Long.MIN_VALUE define the boundaries of the 64-bit long type.
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Coderanch
coderanch.com › t › 401851 › java › Maximum-digits-allowed-literal
Maximum digits allowed for each literal (Beginning Java forum at Coderanch)
NUMERIC INTEGRALS... byte: 8 bits short: 16 bits int: 32 bits long: 64 bits NUMERIC FLOATING POINT... float: 32 bits double: 64 bits SPECIAL CASES... char: 16 bits boolean: 1 bit Once you know this, the next step is to understand how values are represented in binary for each type.
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Grails
grails.asia › maximum-value-of-long-in-java
Maximum Value of Long in Java - Grails Cookbook
And when you when you diminish one from 9,223,372,036,854,775,808, that will bring you the maximum value for long values which is 9,223,372,036,854,775,807 . Check out the code snippet from the Long class that defines the constant maximum value of Long in Java:
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Deep Java
digibeatrix.com › home › java fundamentals › java long max value: long.max_value, range, and overflow (with examples)
Java long Max Value: Long.MAX_VALUE, Range, and Overflow (With Examples) - Deep Java
1 month ago - Do not calculate it directly. Always use: ... Math.pow() returns a double and is therefore inaccurate for large integers. If the range is within about 2.1 billion → use int ... Use long for DB BIGINT columns and timestamps. The maximum value has 19 digits: 9223372036854775807
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Stack Overflow
stackoverflow.com › questions › 16546038 › a-long-bigger-than-long-max-value
java - A long bigger than Long.MAX_VALUE - Stack Overflow
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106

That method can't return true. That's the point of Long.MAX_VALUE. It would be really confusing if its name were... false. Then it should be just called Long.SOME_FAIRLY_LARGE_VALUE and have literally zero reasonable uses. Just use Android's isUserAGoat, or you may roll your own function that always returns false.

Note that a long in memory takes a fixed number of bytes. From Oracle:

long: The long data type is a 64-bit signed two's complement integer. It has a minimum value of -9,223,372,036,854,775,808 and a maximum value of 9,223,372,036,854,775,807 (inclusive). Use this data type when you need a range of values wider than those provided by int.

As you may know from basic computer science or discrete math, there are 2^64 possible values for a long, since it is 64 bits. And as you know from discrete math or number theory or common sense, if there's only finitely many possibilities, one of them has to be the largest. That would be Long.MAX_VALUE. So you are asking something similar to "is there an integer that's >0 and < 1?" Mathematically nonsensical.

If you actually need this for something for real then use BigInteger class.

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You can't. If you have a method called isBiggerThanMaxLong(long) it should always return false.

If you were to increment the bits of Long.MAX_VALUE, the next value should be Long.MIN_VALUE. Read up on twos-complement and that should tell you why.

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Quora
quora.com › In-Java-how-many-digits-short-can-int-and-long-can-store
In Java, how many digits short can int and long can store? - Quora
Here is the bit counts except sign bit, and decimal digits: float: 23 bit, 6 ~ 7 decimal digits, double: 52 bit, 15 ~ 16 decimal digits, byte: 7 bit, 2 ~ 3 decimal digits, short: 15 bit, 4 ~ 5 decimal digits, int: 31 bit,...
Find elsewhere
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Javadevnotes
javadevnotes.com › java-long-max-value
Java Long Max Value - JavaDevNotes
The Java Long Max Value is 9,223,372,036,854,775,807.
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Microsoft Learn
learn.microsoft.com › en-us › dotnet › api › java.lang.long.maxvalue
Long.MaxValue Field (Java.Lang) | Microsoft Learn
[Android.Runtime.Register("MAX_VALUE")] public const long MaxValue = 9223372036854775807; [<Android.Runtime.Register("MAX_VALUE")>] val mutable MaxValue : int64 ... Java documentation for java.lang.Long.MAX_VALUE.
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Reddit
reddit.com › r/javahelp › which is larger? long vs double
r/javahelp on Reddit: Which is larger? Long vs Double
January 19, 2023 -

I’ve tried looking for definitive answers but the only difference I see seems to be based on the precision of the numbers?

Which data type is larger and which one is smaller?

Top answer
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13
double is made of 1 bit sign 52 bit mantissa and 11 bit exponent and long is made of 1 bit sign and 63 bit number. So double can have larger values, and they both take 64 bits in your memory. So double has the precision of at most 16 digits and long of at most 19 digits. (Also, a double can have a value of Infinity) If you're looking for an object that can store very large numbers, use BigInteger or BigDecimal, their value is only limited by how much memory your computer has and they can do precise math.
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If you're asking about the amount of space that will be occupied by a long or a double, then the answer is that they're both the same: 64 bits. If you're asking about the range of values that can be represented with a long or a double, then the answer is that double has a larger range of values, but it suffers from floating-point precision issues; meaning that it can't represent most values in its range (which gets especially noticeable with larger values).
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i-Programmer
i-programmer.info › ebooks › modern-java › 5423-java-data-types-numeric-data.html
Java Data Types - Numeric Data
Programming book reviews, programming tutorials,programming news, C#, Ruby, Python,C, C++, PHP, Visual Basic, Computer book reviews, computer history, programming history, joomla, theory, spreadsheets and more.
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GeeksforGeeks
geeksforgeeks.org › java › integer-max_value-and-integer-min_value-in-java-with-examples
Integer.MAX_VALUE and Integer.MIN_VALUE in Java with Examples - GeeksforGeeks
July 12, 2025 - Example 2: Trying to initialize a variable value Integer.MAX_VALUE + 1 ... // Java program to show what happens when // a value greater than Integer.MAX_VALUE // is stored in an int variable class GFG { // Driver code public static void main(String[] arg) { try { System.out.println( "Trying to initialize" + " a N with value" + " Integer.MAX_VALUE + 1"); // Try to store value Integer.MAX_VALUE + 1 int N = Integer.MAX_VALUE + 1; // Print the value of N System.out.println("N = " + N); } catch (Exception e) { System.out.println(e); } } }
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iO Flood
ioflood.com › blog › integer-max-value-java
Java's Integer.MAX_VALUE Explained: A Complete Guide
March 11, 2024 - The long data type in Java can hold much larger values than int. The maximum value of long is 9,223,372,036,854,775,807, which is retrieved by Long.MAX_VALUE.
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Dirask
dirask.com › posts › Java-get-long-max-value-xpJPV1
Java - get long max value
Short solution: Java Long max value is 9223372036854775807 Additionally short solution to get long min value: Java Long min value is -9223372036854775808 1. Alt...
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Runestone Academy
runestone.academy › ns › books › published › apcsareview › VariableBasics › minAndMax.html
3.7. Integer Min and Max — AP CSA Java Review - Obsolete
In 32 bits of space with one bit ... that many values. Why is there one more negative number than positive number? It is because 0 is considered a positive number. What do the last two lines print out? Did this surprise you? Java will actually return the maximum integer value ...
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iO Flood
ioflood.com › blog › java-long
The Long Data Type in Java: A Detailed How-To Guide
February 26, 2024 - As mentioned earlier, each numeric data type in Java has a specific range of values it can hold. If a calculation results in a value that is outside this range, it can lead to numeric overflow (if the value is too large) or underflow (if the value is too small). For example, if you add 1 to the maximum value an int can hold, you’ll get numeric overflow, and the result will wrap around to the minimum value an int can hold.
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Stack Overflow
stackoverflow.com › questions › 45507936 › max-does-not-accept-10-digits-on-long-wrapper-type
java - @Max does not accept 10 digits on long wrapper type - Stack Overflow
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The parameter to @Max is defined as a long. Setting it to, for example, 42 means passing the int value 42, which gets cast to the long value 42L and then set. Standard operating procedure, really. Nothing special about @Max going on here.

When you pass 9999999999 it tries to interpret it as an int and fails. Eclipse is warning you of this, just perhaps not terribly clearly. To pass in 9999999999 you need to do it as a long which means designating the constraint as @Max(9999999999L).

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Stack Overflow
stackoverflow.com › questions › 28464246 › how-can-i-get-the-max-decimal-value-of-n-digit-number-in-java
math - How can I get the max decimal value of n-digit number in Java? - Stack Overflow
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if (value >= 0 && value < Math.pow(10, MAX))
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Use log base 10 to get the number of digits in a base 10 number

if ((int)(Math.log10(value) + 1) <= MAX) {
    ...
}

If you don't have access to log10, you can use normal log to do this:

int length = (int)(Math.log(value) / Math.log(10)) + 1;
if (length <= MAX) {
    ...
}

Note this also works for any base, so using the second method above, you can replace the 10 with any base and you have the length of that number in the given base