Once in an interview I was asked the difference between JSON and Dictionary. So I decided to write a blog post about it. Do check it out. Link
python - Converting dictionary to JSON - Stack Overflow
python - Converting JSON String to Dictionary Not List - Stack Overflow
convert JSON list to dictionary
JSON Effectively is a Dictionary? Change My Mind
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json.dumps() converts a dictionary to str object, not a json(dict) object! So you have to load your str into a dict to use it by using json.loads() method
See json.dumps() as a save method and json.loads() as a retrieve method.
This is the code sample which might help you understand it more:
import json
r = {'is_claimed': 'True', 'rating': 3.5}
r = json.dumps(r)
loaded_r = json.loads(r)
loaded_r['rating'] #Output 3.5
type(r) #Output str
type(loaded_r) #Output dict
json.dumps() returns the JSON string representation of the python dict. See the docs
You can't do r['rating'] because r is a string, not a dict anymore
Perhaps you meant something like
r = {'is_claimed': 'True', 'rating': 3.5}
json = json.dumps(r) # note i gave it a different name
file.write(str(r['rating']))
Your JSON is an array with a single object inside, so when you read it in you get a list with a dictionary inside. You can access your dictionary by accessing item 0 in the list, as shown below:
json1_data = json.loads(json1_str)[0]
Now you can access the data stored in datapoints just as you were expecting:
datapoints = json1_data['datapoints']
I have one more question if anyone can bite: I am trying to take the average of the first elements in these datapoints(i.e. datapoints[0][0]). Just to list them, I tried doing datapoints[0:5][0] but all I get is the first datapoint with both elements as opposed to wanting to get the first 5 datapoints containing only the first element. Is there a way to do this?
datapoints[0:5][0] doesn't do what you're expecting. datapoints[0:5] returns a new list slice containing just the first 5 elements, and then adding [0] on the end of it will take just the first element from that resulting list slice. What you need to use to get the result you want is a list comprehension:
[p[0] for p in datapoints[0:5]]
Here's a simple way to calculate the mean:
sum(p[0] for p in datapoints[0:5])/5. # Result is 35.8
If you're willing to install NumPy, then it's even easier:
import numpy
json1_file = open('json1')
json1_str = json1_file.read()
json1_data = json.loads(json1_str)[0]
datapoints = numpy.array(json1_data['datapoints'])
avg = datapoints[0:5,0].mean()
# avg is now 35.8
Using the , operator with the slicing syntax for NumPy's arrays has the behavior you were originally expecting with the list slices.
Here is a simple snippet that read's in a json text file from a dictionary. Note that your json file must follow the json standard, so it has to have " double quotes rather then ' single quotes.
Your JSON dump.txt File:
{"test":"1", "test2":123}
Python Script:
import json
with open('/your/path/to/a/dict/dump.txt') as handle:
dictdump = json.loads(handle.read())
I must first preface this with the fact that I’m extremely new to python. Like just started learning it a little over a week ago.
I have been racking my brain over how to convert a json object I opened and loaded into a dictionary from a list so I can use the get() function nested within a for loop to do a student ID comparison from another json file (key name in that file is just ID).
Below is the command I’m trying to load the json file:
With open(‘file.json’) as x: object=json.load(x)
When I print(type(object)), it shows up as class list.
Here’s a sample of what the json looks like:
[
{
“Name”: “Steel”,
“StudentID”: 3458274
“Tuition”: 24.99
},
{
“Name”: “Joe”,
“StudentID”: 5927592
“Tuition”: 14.99
}
]
HELP! Thank you!
Isn't JSON format effectively a Python dictionary, in that they follow the same format? Isn't that right? Thanks guys!