1) Assuming you have the JSON libraries on your path (from www.json.org), it's pretty easy.
import org.json.JSONTokener;
...
URI uri = new URI("http://someserver/data.json");
JSONTokener tokener = new JSONTokener(uri.toURL().openStream());
JSONObject root = new JSONObject(tokener);
From there, you can address the various parts of the JSON object. Take a look at the Javadocs for the specifics. https://developer.android.com/reference/org/json/package-summary.html
Answer from JohnnyO on Stack Overflow1) Assuming you have the JSON libraries on your path (from www.json.org), it's pretty easy.
import org.json.JSONTokener;
...
URI uri = new URI("http://someserver/data.json");
JSONTokener tokener = new JSONTokener(uri.toURL().openStream());
JSONObject root = new JSONObject(tokener);
From there, you can address the various parts of the JSON object. Take a look at the Javadocs for the specifics. https://developer.android.com/reference/org/json/package-summary.html
Here is the most universal solution, which allows to parse any JSON type into appropriate Java type:
Object json = new JSONTokener(response).nextValue();
Then you can determine resulting type and handle it appropriately.
Videos
The org.json library is easy to use.
Just remember (while casting or using methods like getJSONObject and getJSONArray) that in JSON notation
[ … ]represents an array, so library will parse it toJSONArray{ … }represents an object, so library will parse it toJSONObject
Example code below:
import org.json.*;
String jsonString = ... ; //assign your JSON String here
JSONObject obj = new JSONObject(jsonString);
String pageName = obj.getJSONObject("pageInfo").getString("pageName");
JSONArray arr = obj.getJSONArray("posts"); // notice that `"posts": [...]`
for (int i = 0; i < arr.length(); i++)
{
String post_id = arr.getJSONObject(i).getString("post_id");
......
}
You may find more examples from: Parse JSON in Java
Downloadable jar: http://mvnrepository.com/artifact/org.json/json
For the sake of the example lets assume you have a class Person with just a name.
private class Person {
public String name;
public Person(String name) {
this.name = name;
}
}
Jackson (Maven)
My personal favourite and probably the most widely used.
ObjectMapper mapper = new ObjectMapper();
// De-serialize to an object
Person user = mapper.readValue("{\"name\": \"John\"}", Person.class);
System.out.println(user.name); //John
// Read a single attribute
JsonNode nameNode = mapper.readTree("{\"name\": \"John\"}");
System.out.println(nameNode.get("name").asText());
Google GSON (Maven)
Gson g = new Gson();
// De-serialize to an object
Person person = g.fromJson("{\"name\": \"John\"}", Person.class);
System.out.println(person.name); //John
// Read a single attribute
JsonObject jsonObject = new JsonParser().parseString("{\"name\": \"John\"}").getAsJsonObject();
System.out.println(jsonObject.get("name").getAsString()); //John
Org.JSON (Maven)
This suggestion is listed here simply because it appears to be quite popular due to stackoverflow reference to it. I would not recommend using it as it is more a proof-of-concept project than an actual library.
JSONObject obj = new JSONObject("{\"name\": \"John\"}");
System.out.println(obj.getString("name")); //John