How about:
>>> any(isinstance(e, int) and e > 0 for e in [1,2,'joe'])
True
It also works with all() of course:
>>> all(isinstance(e, int) and e > 0 for e in [1,2,'joe'])
False
Answer from Antoine P. on Stack OverflowVideos
How about:
>>> any(isinstance(e, int) and e > 0 for e in [1,2,'joe'])
True
It also works with all() of course:
>>> all(isinstance(e, int) and e > 0 for e in [1,2,'joe'])
False
any function returns True when any condition is True.
>>> any(isinstance(e, int) and e > 0 for e in [0 ,0, 1])
True # Returns True because 1 is greater than 0.
>>> any(isinstance(e, int) and e > 0 for e in [0 ,0, 0])
False # Returns False because not a single condition is True.
Actually,the concept of any function is brought from Lisp or you can say from the function programming approach. There is another function which is just opposite to it is all
>>> all(isinstance(e, int) and e > 0 for e in [1, 33, 22])
True # Returns True when all the condition satisfies.
>>> all(isinstance(e, int) and e > 0 for e in [1, 0, 1])
False # Returns False when a single condition fails.
These two functions are really cool when used properly.
Hi! Just a simple question, I was wondering how to create a list of different lambda functions like so:
[(lambda x: x*i) for i in range(3)]
Ideally, this should return an output like this:
[lambda x: x*0, lambda x: x*1, lambda x: x*2]
However, the actual output is like so:
[lambda x: x*2, lambda x: x*2, lambda x: x*2]
How would I go about producing the desired output? Thanks!
I understand what the lambda function is, its an anonymous function in one line, however why using it, and what really is it? I mean every code I looked at, has it and don't forget map() reduce and filter() function are used with it, what are all these used for and why, I did my research but I still don't understand, (I have a baby's brain ๐ง y'all)