You can use this maven dependency : http://mvnrepository.com/artifact/org.json/json/20160212

It's very simple to understated and use. ex:

JSONObject obj = "YOUR_JSON_STRING";
JSONArray result = obj.getJSONArray("YOUR_STRING_KEY");

for(JSONObject elem : result){
   String out = elem.getString("xxx");
}

More you can read at : https://developer.android.com/reference/org/json/JSONArray.html Good luck

Your question isn't very clear. From your own answer, I can tell better what you are trying to do:

public static String[] removeElements(String[] input, String deleteMe) {
    List result = new LinkedList();

    for(String item : input)
        if(!deleteMe.equals(item))
            result.add(item);

    return result.toArray(input);
}

NB: This is untested. Error checking is left as an exercise to the reader (I'd throw IllegalArgumentException if either input or deleteMe is null; an empty list on null list input doesn't make sense. Removing null Strings from the array might make sense, but I'll leave that as an exercise too; currently, it will throw an NPE when it tries to call equals on deleteMe if deleteMe is null.)

Choices I made here:

I used a LinkedList. Iteration should be just as fast, and you avoid any resizes, or allocating too big of a list if you end up deleting lots of elements. You could use an ArrayList, and set the initial size to the length of input. It likely wouldn't make much of a difference.

If you want to remove an element from the ArrayNode, just

final JsonNode json = objectMapper.readTree(new File("savefiles.json"));

if (json.isArray()) {
    for (final Iterator<JsonNode> i = json.elements(); i.hasNext(); ) {
        final JsonNode jsonNode = i.next();

        if ("1".equals(jsonNode.get("name").asText())) {
            i.remove();
        }
    }
}

This will not create a new instance. The original TreeNode (which is an ArrayNode) is maintained.
Note also the .asText() while comparing.

A Stream version is

final ArrayNode filtered =
        StreamSupport.stream(json.spliterator(), false)
                     .filter(e -> !"1".equals(e.get("name").asText()))
                     .collect(Collector.of(
                             objectMapper::createArrayNode,
                             (array, element) -> array.add(element),
                             (result, toMerge) -> result.addAll(toMerge)
                     ));