String myString = "1234";
int foo = Integer.parseInt(myString);
If you look at the Java documentation you'll notice the "catch" is that this function can throw a NumberFormatException, which you can handle:
int foo;
try {
foo = Integer.parseInt(myString);
}
catch (NumberFormatException e) {
foo = 0;
}
(This treatment defaults a malformed number to 0, but you can do something else if you like.)
Alternatively, you can use an Ints method from the Guava library, which in combination with Java 8's Optional, makes for a powerful and concise way to convert a string into an int:
import com.google.common.primitives.Ints;
int foo = Optional.ofNullable(myString)
.map(Ints::tryParse)
.orElse(0)
Answer from Rob Hruska on Stack OverflowString myString = "1234";
int foo = Integer.parseInt(myString);
If you look at the Java documentation you'll notice the "catch" is that this function can throw a NumberFormatException, which you can handle:
int foo;
try {
foo = Integer.parseInt(myString);
}
catch (NumberFormatException e) {
foo = 0;
}
(This treatment defaults a malformed number to 0, but you can do something else if you like.)
Alternatively, you can use an Ints method from the Guava library, which in combination with Java 8's Optional, makes for a powerful and concise way to convert a string into an int:
import com.google.common.primitives.Ints;
int foo = Optional.ofNullable(myString)
.map(Ints::tryParse)
.orElse(0)
For example, here are two ways:
Integer x = Integer.valueOf(str);
// or
int y = Integer.parseInt(str);
There is a slight difference between these methods:
valueOfreturns a new or cached instance ofjava.lang.IntegerparseIntreturns primitiveint.
The same is for all cases: Short.valueOf/parseShort, Long.valueOf/parseLong, etc.
Videos
There are multiple ways:
String.valueOf(number)(my preference)"" + number(I don't know how the compiler handles it, perhaps it is as efficient as the above)Integer.toString(number)
Integer class has static method toString() - you can use it:
int i = 1234;
String str = Integer.toString(i);
Returns a String object representing the specified integer. The argument is converted to signed decimal representation and returned as a string, exactly as if the argument and radix 10 were given as arguments to the toString(int, int) method.